Python - 大于 K 的数字平均值

给定元素列表，提取平均位数大于 K 的元素。

Input : test_list = [633, 719, 8382, 119, 327], K = 5 
Output : [719, 8382] 
Explanation : (7 + 1 + 9) / 3 = 5.6 and (8 + 3 + 8 + 2) / 4 = 5.2 , both of which are greater than 5, hence returned.

Input : test_list = [633, 719, 8382, 96], K = 5 
Output : [719, 8382, 96] 
Explanation : All the elements are displayed in output whose digit average is greater than 5.

方法 #1：使用列表推导 + sum() + len()

在这里，我们使用sum()计算数字总和，然后将总和除以元素长度以获得平均值，如果大于 K 则添加结果。

Python3

# Python3 code to demonstrate working of
# Average digit greater than K
# Using sum() + len() + list comprehension
  
# initializing list
test_list = [633, 719, 8382, 119, 327]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 5
  
# getting average and checking if greater than K
res = [sub for sub in test_list if sum(
    [int(ele) for ele in str(sub)]) / len(str(sub)) >= K]
  
# printing result
print("Filtered List : " + str(res))

输出：

The original list is : [633, 719, 8382, 119, 327]
Filtered List : [719, 8382]

方法#2：使用 sum() + len() + filter() + lambda

在这里，过滤操作是使用filter()和lambda来执行的，其余的所有操作都按照上面的方法处理。

蟒蛇3

# Python3 code to demonstrate working of
# Average digit greater than K
# Using sum() + len() + filter() + lambda
  
# initializing list
test_list = [633, 719, 8382, 119, 327]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 5
  
# getting average and checking if greater than K
# using filter() and lambda to filter
res = list(filter(lambda sub: sum(
    [int(ele) for ele in str(sub)]) / len(str(sub)) >= K, test_list))
  
# printing result
print("Filtered List : " + str(res))

输出：

The original list is : [633, 719, 8382, 119, 327]
Filtered List : [719, 8382]