Python中的 numpy.ma.ediff1d()函数

numpy.ma.ediff1d()函数返回数组的连续元素之间的差异。

Syntax : numpy.ma.ediff1d(arr, to_end = None, to_begin = None) 

Parameters : 
arr : [array_like] Input array. 
to_end : [array_like, optional] Number to append at the end of the returned differences. 
to_begin : [array_like, optional] Number to prepend at the beginning of the returned differences. 

Return : Return the differences between consecutive elements of an array. 

代码#1：

Python3

# Python program explaining
# numpy.ma.ediff1d() function
  
# importing numpy as geek
import numpy as geek
  
arr = geek.array([3, 5, 8, 4, 12])
  
gfg = geek.ma.ediff1d(arr)
  
print(gfg)

输出：

[ 2  3 -4  8]

代码#2：

蟒蛇3

# Python program explaining
# numpy.ma.ediff1d() function
  
# importing numpy as geek
import numpy as geek
  
arr = geek.array([3, 5, 8, 4, 12])
  
gfg = geek.ma.ediff1d(arr, to_begin=geek.array([-23, 0]), to_end=25)
  
print(gfg)

输出：

[-23 0 2 3 -4 8 25]