Python - 从字典嵌套中删除 K 值项

给定具有多个嵌套的字典，删除所有值为 K 的键。

Input : [{“Gfg” : {“a” : 5, “b” : 8, “c” : 9}}, {“is” : {“j” : 8, “k” : 10}}, {“Best” : {“i” : 16}}], K = 8
Output : [{‘a’: 5}, {‘c’: 9}, {‘k’: 10}, {‘i’: 16}]
Explanation : All the keys with value 8, (“b”, “j”) has been removed.

Input : [{“Gfg” : {“a” : 5, “b” : 8, “c” : 9}}, {“is” : {“j” : 8, “k” : 10}}, {“Best” : {“i” : 16}}], K = 5
Output : [{‘c’: 9}, {‘k’: 10}, {‘i’: 16}, {“j” : 8}, {“b” : 8}]
Explanation : “a” with 5 as value removed.

方法#1：使用循环+字典理解

上述功能的组合可以用来解决这个问题。在此，我们使用循环迭代所有嵌套键。并删除值。这种方法适用于字典的单级嵌套。

Python3

# Python3 code to demonstrate working of 
# Remove K value items from dictionary nestings
# Using dictionary comprehension + loop
  
# initializing list
test_list = [{"Gfg" : {"a" : 5, "b" : 8, "c" : 9}},
             {"is" : {"f" : 8, "j" : 8, "k" : 10}},
             {"Best" : {"i" : 16}}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K 
K = 8
  
res = list()
  
for sub in test_list:
    for key, val in sub.items():
          
        # iterating for 1st nesting only
        for key1, val1 in val.items():
            if val1 != K:
                res.append({key1 : val1})
  
# printing result 
print("The dictionary after value removal : " + str(res))

输出

The original list is : [{‘Gfg’: {‘a’: 5, ‘b’: 8, ‘c’: 9}}, {‘is’: {‘f’: 8, ‘j’: 8, ‘k’: 10}}, {‘Best’: {‘i’: 16}}]
The dictionary after value removal : [{‘a’: 5}, {‘c’: 9}, {‘k’: 10}, {‘i’: 16}]

方法#2：使用递归+循环（用于多重嵌套）

这是可以执行此任务的另一种方式。在此，我们解决了一个更通用的问题，即迎合内部字典元素以及使用递归。

Python3

# Python3 code to demonstrate working of 
# Remove K value items from dictionary nestings
# Using recursion + loop (For multiple nesting)
  
res = []
  
# helper function to solve problem
def hlper_fnc(test_dict):
    for key in test_dict:
        if type(test_dict[key]) == dict:
            hlper_fnc(test_dict[key])
        else:
            if test_dict[key] != K:
                res.append({key : test_dict[key]})
  
# initializing dictionary
test_dict = {"Gfg" : {"a" : 5, "b" : 8, "c" : 9},
             "is" : {"f" : 8, "l" : { "j" : 8, "k" : 10}},
             "Best" : {"i" : {"k" : { "o" : 8}}}}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing K 
K = 8
  
# computing result
hlper_fnc(test_dict)
  
# printing result 
print("The dictionary after value removal : " + str(res)) 

输出

The original dictionary is : {‘Gfg’: {‘a’: 5, ‘b’: 8, ‘c’: 9}, ‘is’: {‘f’: 8, ‘l’: {‘j’: 8, ‘k’: 10}}, ‘Best’: {‘i’: {‘k’: {‘o’: 8}}}}
The dictionary after value removal : [{‘a’: 5}, {‘c’: 9}, {‘k’: 10}]