Python – 将元组矩阵转换为元组列表

给定一个元组矩阵，展平为元组列表，每个元组代表每一列。

Input : test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)]]
Output : [(4, 7, 10, 18), (5, 8, 13, 17)]
Explanation : All column number elements contained together.

Input : test_list = [[(4, 5)], [(10, 13)]]
Output : [(4, 10), (5, 13)]
Explanation : All column number elements contained together.

方法 #1：使用列表理解 + zip()

在此，我们使用列表理解执行展平任务，并使用 zip() 执行列配对以呈现为元组对。

Python3

# Python3 code to demonstrate working of 
# Convert Tuple Matrix to Tuple List
# Using list comprehension + zip()
  
# initializing list
test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# flattening 
temp = [ele for sub in test_list for ele in sub]
  
# joining to form column pairs
res = list(zip(*temp))
  
# printing result 
print("The converted tuple list : " + str(res))

输出

The original list is : [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]]
The converted tuple list : [(4, 7, 10, 18, 0, 10), (5, 8, 13, 17, 4, 1)]

方法 #2：使用 chain.from_iterable() + zip()

在此，使用 chain.from_iterable() 执行展平任务，并使用 zip() 执行列配对任务。

Python3

# Python3 code to demonstrate working of 
# Convert Tuple Matrix to Tuple List
# Using chain.from_iterable() + zip()
from itertools import chain
  
# initializing list
test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# flattening using from_iterable
res = list(zip(*chain.from_iterable(test_list)))
  
# printing result 
print("The converted tuple list : " + str(res))

输出

The original list is : [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]]
The converted tuple list : [(4, 7, 10, 18, 0, 10), (5, 8, 13, 17, 4, 1)]