📜  查找有理数的LCM

📅  最后修改于: 2021-04-23 18:10:35             🧑  作者: Mango

给定一个有理数数组,任务是找到这些数的LCM。

例子:

Input : vect[] = {2/7, 3/14, 5/3}
Output : 30/1

Input : vect[] = {3/14, 5/3}
Output : 15/1

Input : vect[] = {3/4, 3/2}
Output : 3/2

首先找到所有有理数分子的lcm,然后找到所有有理数分母的gcd,然后将所有分子的lcm /所有分母的gcd除以有理数的lcm。

公式:-

LCM of all the numerator of Rational number's
lcm = -----------------------------------------------
      GCD of all the denominator of Rational number's
C++
// CPP program to find LCM of given array
#include 
using namespace std;
  
// get lcm of two numbers
int LCM(int a, int b)
{
    return (a * b) / (__gcd(a, b));
}
  
// Finds LCM of numerators
int lcmOfNumerator(vector > vect)
{
    // calculate the lcm of all numerators
    int lcm = vect[0].first;
    for (int i = 1; i < vect.size(); i++) 
        lcm = LCM(vect[i].first, lcm); 
  
    // return all numerator lcm
    return lcm;
}
  
// Get GCD of all the denominators
int gcdOfDemoninators(vector > vect)
{
    // calculate the gcd of all the denominators
    int gcd = vect[0].second;
    for (int i = 1; i < vect.size(); i++) 
        gcd = __gcd(vect[i].second, gcd); 
  
    // return all denominator gcd
    return gcd;
}
  
// find lcm of all the rational number
void lcmOfRationals(vector > vect)
{
    // return the LCM of all numerator/ GCD of all 
    // denominator
    cout << lcmOfNumerator(vect) << "/"
        << gcdOfDemoninators(vect);
}
  
// Driver code
int main()
{
    vector > vect;
  
    // give rational number 2/7, 3/14, 5/3
    // make pair as a numerator and denominator
    vect.push_back(make_pair(2, 7));
    vect.push_back(make_pair(3, 14));
    vect.push_back(make_pair(5, 3));
    lcmOfRationals(vect);
    return 0;
}


Java
// JAVA program to find LCM of given array
import java.util.*;
  
class GFG
{
      
static class pair
{ 
    int first, second; 
    public pair(int first, int second) 
    { 
        this.first = first; 
        this.second = second; 
    } 
}
  
// get lcm of two numbers
static int LCM(int a, int b)
{
    return (a * b) / (__gcd(a, b));
}
static int __gcd(int a, int b) 
{ 
    return b == 0? a:__gcd(b, a % b);     
}
  
// Finds LCM of numerators
static int lcmOfNumerator(Vector vect)
{
    // calculate the lcm of all numerators
    int lcm = vect.get(0).first;
    for (int i = 1; i < vect.size(); i++) 
        lcm = LCM(vect.get(i).first, lcm); 
  
    // return all numerator lcm
    return lcm;
}
  
// Get GCD of all the denominators
static int gcdOfDemoninators(Vector vect)
{
    // calculate the gcd of all the denominators
    int gcd = vect.get(0).second;
    for (int i = 1; i < vect.size(); i++) 
        gcd = __gcd(vect.get(i).second, gcd); 
  
    // return all denominator gcd
    return gcd;
}
  
// find lcm of all the rational number
static void lcmOfRationals(Vector vect)
{
    // return the LCM of all numerator/ GCD of all 
    // denominator
    System.out.print(lcmOfNumerator(vect)+ "/"
        + gcdOfDemoninators(vect));
}
  
// Driver code
public static void main(String[] args)
{
    Vector vect = new Vector();
  
    // give rational number 2/7, 3/14, 5/3
    // make pair as a numerator and denominator
    vect.add(new pair(2, 7));
    vect.add(new pair(3, 14));
    vect.add(new pair(5, 3));
    lcmOfRationals(vect);
}
}
  
// This code is contributed by Rajput-Ji


Python
# Python program to find LCM of given array 
import math
  
# get lcm of two numbers 
def LCM(a, b):
      
    return (a * b) // (math.gcd(a, b)) 
  
# Finds LCM of numerators 
def lcmOfNumerator(vect):
  
    # calculate the lcm of all numerators 
    lcm = vect[0][0]
    for i in range(1, len(vect)):
        lcm = LCM(vect[i][0], lcm) 
      
    # return all numerator lcm 
    return lcm 
  
# Get GCD of all the denominators 
def gcdOfDemoninators(vect):
      
    # calculate the gcd of all the denominators 
    gcd = vect[0][1] 
    for i in range(1, len(vect)):
        gcd = math.gcd(vect[i][1], gcd) 
          
    # return all denominator gcd 
    return gcd 
  
# find lcm of all the rational number 
def lcmOfRationals(vect):
      
    # return the LCM of all numerator/ GCD of all 
    # denominator 
    print(lcmOfNumerator(vect), "/", 
            gcdOfDemoninators(vect), sep = "")
  
  
# Driver code 
  
vect = []
  
# give rational number 2/7, 3/14, 5/3 
# make pair as a numerator and denominator 
vect.append((2, 7)) 
vect.append((3, 14)) 
vect.append((5, 3)) 
lcmOfRationals(vect) 
  
# This code is contributed by SHUBHAMSINGH10


C#
// C# program to find LCM of given array
using System;
using System.Collections.Generic;
  
class GFG
{
      
class pair
{ 
    public int first, second; 
    public pair(int first, int second) 
    { 
        this.first = first; 
        this.second = second; 
    } 
}
  
// get lcm of two numbers
static int LCM(int a, int b)
{
    return (a * b) / (__gcd(a, b));
}
static int __gcd(int a, int b) 
{ 
    return b == 0? a:__gcd(b, a % b);     
}
  
// Finds LCM of numerators
static int lcmOfNumerator(List vect)
{
    // calculate the lcm of all numerators
    int lcm = vect[0].first;
    for (int i = 1; i < vect.Count; i++) 
        lcm = LCM(vect[i].first, lcm); 
  
    // return all numerator lcm
    return lcm;
}
  
// Get GCD of all the denominators
static int gcdOfDemoninators(List vect)
{
    // calculate the gcd of all the denominators
    int gcd = vect[0].second;
    for (int i = 1; i < vect.Count; i++) 
        gcd = __gcd(vect[i].second, gcd); 
  
    // return all denominator gcd
    return gcd;
}
  
// find lcm of all the rational number
static void lcmOfRationals(List vect)
{
    // return the LCM of all numerator/ GCD of all 
    // denominator
    Console.Write(lcmOfNumerator(vect)+ "/"
        + gcdOfDemoninators(vect));
}
  
// Driver code
public static void Main(String[] args)
{
    List vect = new List();
  
    // give rational number 2/7, 3/14, 5/3
    // make pair as a numerator and denominator
    vect.Add(new pair(2, 7));
    vect.Add(new pair(3, 14));
    vect.Add(new pair(5, 3));
    lcmOfRationals(vect);
}
}
  
// This code is contributed by 29AjayKumar


输出:

30/1