程序计算3D中两点之间的距离

在3维中给定两个坐标(x1，y1，z1)和(x2，y2，z2)。任务是找到它们之间的距离。
例子 ：

Input: x1, y1, z1 = (2, -5, 7)
       x2, y2, z1 = (3, 4, 5)
Output: 9.2736184955

Input: x1, y1, z1 = (0, 0, 0)
       x2, y2, z1 = (1, 1, 1)
Output: 1.73205080757

方法： 3维两点之间的距离的公式即(x1，y1，z1)和(x2，y2，z2)是根据毕达哥拉斯定理得出的，即：
距离= $$\sqrt{(x2-x1)^{2} + (y2-y1)^{2} + (z2-z1)^{2}}$$
下面是上述公式的实现：

C++

// C++ program to find
// distance between
// two points in 3 D.
#include 
#include 
#include 
#include 
using namespace std;
 
// function to print distance
void distance(float x1, float y1,
            float z1, float x2,
            float y2, float z2)
{
    float d = sqrt(pow(x2 - x1, 2) +
                pow(y2 - y1, 2) +
                pow(z2 - z1, 2) * 1.0);
    std::cout << std::fixed;
    std::cout << std::setprecision(2);
    cout << " Distance is " << d;
    return;
}
 
// Driver Code
int main()
{
    float x1 = 2;
    float y1 = -5;
    float z1 = 7;
    float x2 = 3;
    float y2 = 4;
    float z2 = 5;
     
    // function call for distance
    distance(x1, y1, z1,
            x2, y2, z2);
    return 0;
}
 
// This code is contributed
// by Amber_Saxena.

C

// C program to find
// distance between
// two points in 3 D.
#include 
#include
 
// function to print distance
void distance(float x1, float y1,
              float z1, float x2,
              float y2, float z2)
{
    float d = sqrt(pow(x2 - x1, 2) +
                   pow(y2 - y1, 2) +
                   pow(z2 - z1, 2) * 1.0);
    printf("Distance is %f", d);
    return;
}
 
// Driver Code
int main()
{
    float x1 = 2;
    float y1 = -5;
    float z1 = 7;
    float x2 = 3;
    float y2 = 4;
    float z2 = 5;
     
    // function call for distance
    distance(x1, y1, z1,   
             x2, y2, z2);
    return 0;
}
 
// This code is contributed
// by Amber_Saxena.

Java

// Java program to find
// distance between
// two points in 3 D.
import java .io.*;
import java.lang.Math;
 
class GFG
{
     
// Function for
// distance
static void distance(float x1, float y1,
                     float z1, float x2,
                     float y2, float z2)
{
     
    double d = Math.pow((Math.pow(x2 - x1, 2) +
                         Math.pow(y2 - y1, 2) +
                         Math.pow(z2 - z1, 2) *
                                    1.0), 0.5);
    System.out.println("Distance is "+ d);
    return;
}
 
// Driver code
public static void main(String[] args)
{
    float x1 = 2;
    float y1 = -5;
    float z1 = 7;
    float x2 = 3;
    float y2 = 4;
    float z2 = 5;
     
    // function call
    // for distance
    distance(x1, y1, z1,
             x2, y2, z2);
}
}
 
// This code is contributed
// by Amber_Saxena.

Python

# Python program to find distance between
# two points in 3 D.
 
import math
 
# Function to find distance
def distance(x1, y1, z1, x2, y2, z2):
      
    d = math.sqrt(math.pow(x2 - x1, 2) +
                math.pow(y2 - y1, 2) +
                math.pow(z2 - z1, 2)* 1.0)
    print("Distance is ")
    print(d)
 
# Driver Code
x1 = 2
y1 = -5
z1 = 7
x2 = 3
y2 = 4
z2 = 5
 
# function call for distance
distance(x1, y1, z1, x2, y2, z2)

C#

// C# program to find
// distance between
// two points in 3 D.
using System;
 
class GFG
{
     
// Function for
// distance
static void distance(float x1, float y1,
                     float z1, float x2,
                     float y2, float z2)
{
    double d = Math.Pow((Math.Pow(x2 - x1, 2) +
                         Math.Pow(y2 - y1, 2) +
                         Math.Pow(z2 - z1, 2) *
                                   1.0), 0.5);
    Console.WriteLine("Distance is \n" + d);
    return;
}
 
// Driver code
public static void Main()
{
    float x1 = 2;
    float y1 = -5;
    float z1 = 7;
    float x2 = 3;
    float y2 = 4;
    float z2 = 5;
     
    // function call
    // for distance
    distance(x1, y1, z1,
             x2, y2, z2);
}
}
 
// This code is contributed
// by chandan_jnu.

Javascript

 
// javascript program to find
// distance between
// two points in 3 D.   
 
// Function for distance
    function distance(x1 , y1 , z1 , x2 , y2 , z2) {
 
        var d = Math.pow((Math.pow(x2 - x1, 2) +
                Math.pow(y2 - y1, 2) +
                Math.pow(z2 - z1, 2) * 1.0), 0.5);
        document.write("Distance is " + d.toFixed(10));
        return;
    }
 
    // Driver code
     
        var x1 = 2;
        var y1 = -5;
        var z1 = 7;
        var x2 = 3;
        var y2 = 4;
        var z2 = 5;
 
        // function call
        // for distance
        distance(x1, y1, z1, x2, y2, z2);
 
// This code contributed by aashish1995
 

输出：

Distance is 
9.2736184955