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📜  检查八进制数字是偶数还是奇数

📅  最后修改于: 2021-04-25 00:57:49             🧑  作者: Mango

给定八进制数N ,检查它是偶数还是奇数。
例子:

Input: N = 7234
Output: Even

Input: N = 333333333
Output: Odd

天真的方法:

  • 将数字从八进制基数转换为十进制基数。
  • 然后检查数字是偶数还是奇数,将其除以2即可轻松进行检查。

时间复杂度: O(N)
高效的方法:由于八进制数字包含从0到7的数字,因此我们可以简单地检查最后一个数字是否为’0’,’2’,’4’或’6′ 。如果是,则给定的八进制数将为偶数,否则为奇数。
下面是上述方法的实现。

C++
// C++ code to check if a Octal
// number is Even or Odd
 
#include 
using namespace std;
 
// Check if the number is odd or even
string even_or_odd(string N)
{
    int len = N.size();
 
    // Check if the last digit
    // is either '0', '2', '4',
    // or '6'
    if (N[len - 1] == '0'
        || N[len - 1] == '2'
        || N[len - 1] == '4'
        || N[len - 1] == '6')
        return ("Even");
    else
        return ("Odd");
}
 
// Driver code
int main()
{
    string N = "735";
 
    cout << even_or_odd(N);
 
    return 0;
}


Java
// Java code to check if a Octal
// number is Even or Odd
class GFG{
  
// Check if the number is odd or even
static String even_or_odd(String N)
{
    int len = N.length();
  
    // Check if the last digit
    // is either '0', '2', '4',
    // or '6'
    if (N.charAt(len - 1) == '0'
        || N.charAt(len - 1) == '2'
        || N.charAt(len - 1) == '4'
        || N.charAt(len - 1) == '6')
        return ("Even");
    else
        return ("Odd");
}
  
// Driver code
public static void main(String[] args)
{
    String N = "735";
  
    System.out.print(even_or_odd(N));
}
}
 
// This code is contributed by Rajput-Ji


Python 3
# Python 3 code to check if a Octal
# number is Even or Odd
 
# Check if the number is odd or even
def even_or_odd( N):
    l = len(N);
 
    # Check if the last digit
    # is either '0', '2', '4',
    # or '6'
    if (N[l - 1] == '0'or N[l - 1] == '2'or
        N[l - 1] == '4' or N[l - 1] == '6'):
        return ("Even")
    else:
        return ("Odd")
 
# Driver code
N = "735"
 
print(even_or_odd(N))
 
# This code is contributed by ANKITKUMAR34


C#
// C# code to check if a Octal
// number is Even or Odd
using System;
 
public class GFG{
   
// Check if the number is odd or even
static String even_or_odd(String N)
{
    int len = N.Length;
   
    // Check if the last digit
    // is either '0', '2', '4',
    // or '6'
    if (N[len - 1] == '0'
        || N[len - 1] == '2'
        || N[len - 1] == '4'
        || N[len - 1] == '6')
        return ("Even");
    else
        return ("Odd");
}
   
// Driver code
public static void Main(String[] args)
{
    String N = "735";
   
    Console.Write(even_or_odd(N));
}
}
 
// This code contributed by Princi Singh


Javascript


输出:
Odd