这个问题被称为时钟角度问题,我们需要在给定的时间找到模拟时钟的指针之间的角度。
例子:
Input:
h = 12:00
m = 30.00
Output:
165 degree
Input:
h = 3.00
m = 30.00
Output:
75 degree
想法是以12:00(h = 12,m = 0)作为参考。以下是详细步骤。
1.计算小时针和小时针相对于12:00的时针角度。
2.计算小时和分钟中分针相对于12:00的角度。
3.两个角度之间的差是两只手之间的角度。
如何计算相对于12:00的两个角度?
分针在60分钟内移动360度(或在一分钟内6度),时针在12小时内移动360度(或1分钟内0.5度)。在h小时和m分钟中,分针将移动(h * 60 + m)* 6,而时针将移动(h * 60 + m)* 0.5。
C++
// C++ program to find angle between hour and minute hands
#include
using namespace std;
// Utility function to find minimum of two integers
int min(int x, int y)
{
return (x < y)? x: y;
}
int calcAngle(double h, double m)
{
// validate the input
if (h <0 || m < 0 || h >12 || m > 60)
printf("Wrong input");
if (h == 12) h = 0;
if (m == 60)
{
m = 0;
h += 1;
if(h>12)
h = h-12;
}
// Calculate the angles moved
// by hour and minute hands
// with reference to 12:00
float hour_angle = 0.5 * (h * 60 + m);
float minute_angle = 6 * m;
// Find the difference between two angles
float angle = abs(hour_angle - minute_angle);
// Return the smaller angle of two possible angles
angle = min(360 - angle, angle);
return angle;
}
// Driver Code
int main()
{
cout << calcAngle(9, 60) << endl;
cout << calcAngle(3, 30) << endl;
return 0;
}
// This is code is contributed by rathbhupendra
C
// C program to find angle between hour and minute hands
#include
#include
// Utility function to find minimum of two integers
int min(int x, int y) { return (x < y)? x: y; }
int calcAngle(double h, double m)
{
// validate the input
if (h <0 || m < 0 || h >12 || m > 60)
printf("Wrong input");
if (h == 12) h = 0;
if (m == 60)
{
m = 0;
h += 1;
if(h>12)
h = h-12;
}
// Calculate the angles moved by hour and minute hands
// with reference to 12:00
int hour_angle = 0.5 * (h*60 + m);
int minute_angle = 6*m;
// Find the difference between two angles
int angle = abs(hour_angle - minute_angle);
// Return the smaller angle of two possible angles
angle = min(360-angle, angle);
return angle;
}
// Driver Code
int main()
{
printf("%d n", calcAngle(9, 60));
printf("%d n", calcAngle(3, 30));
return 0;
}
Java
// Java program to find angle between hour and minute hands
import java.io.*;
class GFG
{
// Function to calculate the angle
static int calcAngle(double h, double m)
{
// validate the input
if (h <0 || m < 0 || h >12 || m > 60)
System.out.println("Wrong input");
if (h == 12)
h = 0;
if (m == 60)
{
m = 0;
h += 1;
if(h>12)
h = h-12;
}
// Calculate the angles moved by hour and minute hands
// with reference to 12:00
int hour_angle = (int)(0.5 * (h*60 + m));
int minute_angle = (int)(6*m);
// Find the difference between two angles
int angle = Math.abs(hour_angle - minute_angle);
// smaller angle of two possible angles
angle = Math.min(360-angle, angle);
return angle;
}
// Driver Code
public static void main (String[] args)
{
System.out.println(calcAngle(9, 60)+" degree");
System.out.println(calcAngle(3, 30)+" degree");
}
}
// Contributed by Pramod Kumar
Python
# Python program to find angle
# between hour and minute hands
# Function to Calculate angle b/w
# hour hand and minute hand
def calcAngle(h,m):
# validate the input
if (h < 0 or m < 0 or h > 12 or m > 60):
print('Wrong input')
if (h == 12):
h = 0
if (m == 60):
m = 0
h += 1;
if(h>12):
h = h-12;
# Calculate the angles moved by
# hour and minute hands with
# reference to 12:00
hour_angle = 0.5 * (h * 60 + m)
minute_angle = 6 * m
# Find the difference between two angles
angle = abs(hour_angle - minute_angle)
# Return the smaller angle of two
# possible angles
angle = min(360 - angle, angle)
return angle
# Driver Code
h = 9
m = 60
print('Angle ', calcAngle(h,m))
# This code is contributed by Danish Raza
C#
// C# program to find angle between
// hour and minute hands
using System;
class GFG {
// Function to calculate the angle
static int calcAngle(double h, double m)
{
// validate the input
if (h < 0 || m < 0 ||
h > 12 || m > 60)
Console.Write("Wrong input");
if (h == 12)
h = 0;
if (m == 60)
{
m = 0;
h += 1;
if(h>12)
h = h-12;
}
// Calculate the angles moved by hour and
// minute hands with reference to 12:00
int hour_angle = (int)(0.5 * (h * 60 + m));
int minute_angle = (int)(6 * m);
// Find the difference between two angles
int angle = Math.Abs(hour_angle - minute_angle);
// smaller angle of two possible angles
angle = Math.Min(360 - angle, angle);
return angle;
}
// Driver code
public static void Main ()
{
Console.WriteLine(calcAngle(9, 60));
Console.Write(calcAngle(3, 30));
}
}
// This code is contributed by Nitin Mittal.
PHP
12 || $m > 60)
echo "Wrong input";
if ($h == 12) $h = 0;
if ($m == 60) {
$m = 0;
$h += 1;
if($h>12)
$h = $h-12;
}
// Calculate the angles
// moved by hour and
// minute hands with
// reference to 12:00
$hour_angle = 0.5 *
($h * 60 + $m);
$minute_angle = 6 * $m;
// Find the difference
// between two angles
$angle = abs($hour_angle -
$minute_angle);
// Return the smaller angle
// of two possible angles
$angle = min(360 - $angle,
$angle);
return $angle;
}
// Driver Code
echo calcAngle(9, 60), "\n";
echo calcAngle(3, 30), "\n";
// This code is contributed by ajit
?>
Javascript
输出
60
75