📜  设置最右边的未设置位

📅  最后修改于: 2021-04-26 07:54:43             🧑  作者: Mango

给定一个非负数n。问题是设置n的二进制表示形式中最右边的未设置位
例子:

Input : 21
Output : 23
(21)10 = (10101)2
Rightmost unset bit is at position 2(from right) as 
highlighted in the binary representation of 21.
(23)10 = (10111)2
The bit at position 2 has been set.

Input : 2
Output : 3

本文讨论一种方法
这篇文章讨论了另一种方法。
令输入数字为n。 n + 1将使所有位在最右边的未设置位(包括未设置位)之后翻转。因此,执行n |(n + 1)将为我们提供所需的结果。

C++
#include 
 
// sets the rightmost unset bit
// of n and returns the result
int fun(unsigned int n)
{
    return n | (n + 1);
}
 
// Driver Code
int main()
{
    int n = 5;
    printf("The number after setting the");
    printf(" rightmost unset bit %d", fun(n));
    return 0;
}


Java
class GFG {
     
    // sets the rightmost unset bit
    // of n and returns the result
    static int fun(int n)
    {
        return n | (n + 1);
    }
     
    // Driver Code
    public static void main(String[] args)
    {
        int n = 5;
        System.out.printf("The number "
                  + "after setting the");
        System.out.printf(" rightmost "
              + " unset bit %d", fun(n));
    }
}
 
// This code is contributed by Smitha


Python3
# sets the rightmost unset bit
# of n and returns the result
def fun(n):
 
    return n | (n + 1)
 
# Driver Code
n = 5
print("The number after setting the", end="")
print(" rightmost unset bit ", fun(n))
 
# This code is contributed by Smitha


C#
using System;
 
class GFG {
     
    // sets the rightmost unset bit
    // of n and returns the result
    static int fun(int n)
    {
        return n | (n + 1);
    }
     
    // Driver Code
    public static void Main()
    {
        int n = 5;
        Console.Write("The number "
            + "after setting the");
        Console.Write(" rightmost "
           + "unset bit "+ fun(n));
    }
}
 
// This code is contributed by Smitha


PHP


Javascript


输出 :

The number after setting the rightmost unset bit 7