给定数字n,找到第n个二十面体数。二十面体数是表示二十面体(具有20个面的多面体)的比喻数字类。来源:Wiki。
前几个二十面体编号是1、12、48、124、255、456、742、1128、1629…………..
例子 :
Input : 5
Output :255
Input :10
Output :2260
二十面体数的第n个项由下式给出:
以上思想基本实现:
C++
// Icosahedral number to find
// n-th term in C++
#include
using namespace std;
// Function to find
// Icosahedral number
int icosahedralnum(int n)
{
// Formula to calculate nth
// Icosahedral number &
// return it into main function.
return (n * (5 * n * n - 5 * n + 2)) / 2;
}
// Driver Code
int main()
{
int n = 7;
cout << icosahedralnum(n);
return 0;
}
Java
// Icosahedral number to find
// n-th term in Java
import java.io.*;
class GFG {
// Function to find
// Icosahedral number
static int icosahedralnum(int n)
{
// Formula to calculate nth
// Icosahedral number &
// return it into main function.
return (n * (5 * n * n - 5 *
n + 2)) / 2;
}
// Driver Code
public static void main (String[] args)
{
int n = 7;
System.out.println(
icosahedralnum(n));
}
}
// This code is contributed by aj_36.
Python3
# Python 3 Program to find
# nth Icosahedral number
# Icosahedral number
# number function
def icosahedralnum(n) :
# Formula to calculate nth
# Icosahedral number
# return it into main function.
return (n * (5 * n * n -
5 * n + 2)) // 2
# Driver Code
if __name__ == '__main__' :
n = 7
print(icosahedralnum(n))
# This code is contributed aj_36
C#
// Icosahedral number to
// find n-th term in C#
using System;
class GFG
{
// Function to find
// Icosahedral number
static int icosahedralnum(int n)
{
// Formula to calculate
// nth Icosahedral number
// & return it into main
// function.
return (n * (5 * n * n -
5 * n + 2)) / 2;
}
// Driver Code
static public void Main ()
{
int n = 7;
Console.WriteLine(icosahedralnum(n));
}
}
// This code is contributed by ajit
PHP
输出
742