给定一个十进制数作为输入,我们需要编写一个程序将给定的十进制数转换为等效的二进制数。
例子:
Input : 7
Output : 111
Input : 10
Output : 1010
Input: 33
Output: 100001
算法:
- 当数字除以2时,将余数存储在数组中。
- 将数字除以2
- 重复上述两个步骤,直到数字大于零。
- 现在以相反顺序打印阵列。
例如:
如果二进制数是10。
步骤1:10除以2时的余数为零。因此,arr [0] = 0。
步骤2 :将10除以2。新数字是10/2 = 5。
步骤3 :将5除以2时的余数为1。因此,arr [1] = 1。
步骤4 :将5除以2。新数字为5/2 = 2。
步骤5 :2除以2时的余数为零。因此,arr [2] = 0。
步骤6 :将2除以2。新数字为2/2 = 1。
步骤7 :1除以2时的余数为1。因此,arr [3] = 1。
步骤8 :将1除以2。新数字为1/2 = 0。
步骤9 :由于number =0。以相反的顺序打印数组。因此,等效的二进制数是1010。
下图显示了将十进制数17转换为等效二进制数的示例。
以下是上述想法的实现。
C++
// C++ program to convert a decimal
// number to binary number
#include
using namespace std;
// function to convert decimal to binary
void decToBinary(int n)
{
// array to store binary number
int binaryNum[32];
// counter for binary array
int i = 0;
while (n > 0) {
// storing remainder in binary array
binaryNum[i] = n % 2;
n = n / 2;
i++;
}
// printing binary array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << binaryNum[j];
}
// Driver program to test above function
int main()
{
int n = 17;
decToBinary(n);
return 0;
}
Java
// Java program to convert a decimal
// number to binary number
import java.io.*;
class GFG {
// function to convert decimal to binary
static void decToBinary(int n)
{
// array to store binary number
int[] binaryNum = new int[32];
// counter for binary array
int i = 0;
while (n > 0) {
// storing remainder in binary array
binaryNum[i] = n % 2;
n = n / 2;
i++;
}
// printing binary array in reverse order
for (int j = i - 1; j >= 0; j--)
System.out.print(binaryNum[j]);
}
// driver program
public static void main(String[] args)
{
int n = 17;
decToBinary(n);
}
}
// Contributed by Pramod Kumar
Python3
# Python3 program to convert a
# decimal number to binary number
# function to convert
# decimal to binary
def decToBinary(n):
# array to store
# binary number
binaryNum = [0] * n;
# counter for binary array
i = 0;
while (n > 0):
# storing remainder
# in binary array
binaryNum[i] = n % 2;
n = int(n / 2);
i += 1;
# printing binary array
# in reverse order
for j in range(i - 1, -1, -1):
print(binaryNum[j], end = "");
# Driver Code
n = 17;
decToBinary(n);
# This code is contributed by mits
C#
// C# program to convert a decimal
// number to binary number
using System;
public class GFG {
// function to convert decimal
// to binary
static void decToBinary(int n)
{
// array to store binary number
int[] binaryNum = new int[32];
// counter for binary array
int i = 0;
while (n > 0) {
// storing remainder in
// binary array
binaryNum[i] = n % 2;
n = n / 2;
i++;
}
// printing binary array
// in reverse order
for (int j = i - 1; j >= 0; j--)
Console.Write(binaryNum[j]);
}
// Driver Code
public static void Main()
{
int n = 17;
decToBinary(n);
}
}
// This code is contributed by Sam007.
PHP
0)
{
// storing remainder
// in binary array
$binaryNum[$i] = $n % 2;
$n = (int)($n / 2);
$i++;
}
// printing binary array
// in reverse order
for ($j = $i - 1; $j >= 0; $j--)
echo $binaryNum[$j];
}
// Driver Code
$n = 17;
decToBinary($n);
// This code is contributed by m_kit
?>
Javascript
C++
// CPP program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
#include
using namespace std;
// Function that convert Decimal to binary
int decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if (k & 1)
cout << "1";
else
cout << "0";
}
}
// driver code
int main()
{
int n = 32;
decToBinary(n);
}
Java
// Java program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
class gfg {
// Function that convert Decimal to binary
public void decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if ((k & 1) > 0)
System.out.print("1");
else
System.out.print("0");
}
}
}
class geek {
// driver code
public static void main(String[] args)
{
gfg g = new gfg();
int n = 32;
g.decToBinary(n);
}
}
// This code is contributed by mits
Python3
# Python3 program to Decimal
# to binary conversion using
# bitwise operator
# Size of an integer is
# assumed to be 32 bits
# Function that convert
# Decimal to binary
def decToBinary(n):
# Size of an integer is
# assumed to be 32 bits
for i in range(31, -1, -1):
k = n >> i;
if (k & 1):
print("1", end = "");
else:
print("0", end = "");
# Driver Code
n = 32;
decToBinary(n);
# This code is contributed by mits
C#
// C# program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
using System;
class gfg {
// Function that convert Decimal to binary
public void decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if ((k & 1) > 0)
Console.Write("1");
else
Console.Write("0");
}
}
}
class geek {
// driver code
public static int Main()
{
gfg g = new gfg();
int n = 32;
g.decToBinary(n);
return 0;
}
}
PHP
= 0; $i--)
{
$k = $n >> $i;
if ($k & 1)
echo "1";
else
echo "0";
}
}
// Driver Code
$n = 32;
decToBinary($n);
// This code is contributed by aj_36
?>
Javascript
C++
// C++ implementation of the approach
#include
#include
using namespace std;
#define ull unsigned long long int
// Function to return the binary
// equivalent of decimal value N
int decimalToBinary(int N)
{
// To store the binary number
ull B_Number = 0;
int cnt = 0;
while (N != 0) {
int rem = N % 2;
ull c = pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
int main()
{
int N = 17;
cout << decimalToBinary(N);
return 0;
}
Java
// Java implementation of the approach
import java.io.*;
class GFG
{
// Function to return the binary
// equivalent of decimal value N
static int decimalToBinary(int N)
{
// To store the binary number
int B_Number = 0;
int cnt = 0;
while (N != 0)
{
int rem = N % 2;
double c = Math.pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
public static void main (String[] args)
{
int N = 17;
System.out.println (decimalToBinary(N));
}
}
// This code is contribted by ajit.
Python3
# Python3 implementation of the approach
# Function to return the binary
# equivalent of decimal value N
def decimalToBinary(N):
# To store the binary number
B_Number = 0
cnt = 0
while (N != 0):
rem = N % 2
c = pow(10, cnt)
B_Number += rem * c
N //= 2
# Count used to store exponent value
cnt += 1
return B_Number
# Driver code
N = 17
print(decimalToBinary(N))
# This code is contributed by
# SHUBHAMSINGH10
C#
// C# implementation of the approach
using System;
class GFG
{
// Function to return the binary
// equivalent of decimal value N
static int decimalToBinary(int N)
{
// To store the binary number
int B_Number = 0;
int cnt = 0;
while (N != 0)
{
int rem = N % 2;
int c = (int)Math.Pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
static public void Main ()
{
int N = 17;
Console.Write(decimalToBinary(N));
}
}
// This code is contributed by Tushil.
Javascript
C++
//C++ program to convert a decimal mumber
//to its binary form.
//including heaader file
#include
using namespace std;
//Function to convert a decimal mumber
//to its binary form
string decimalToBinary(int n)
{
//finding the binary form of the number and
//coneverting it to string.
string s = bitset<64> (n).to_string();
//Finding the first occurance of "1"
//to strip off the leading zeroes.
const auto loc1 = s.find('1');
if(loc1 != string::npos)
return s.substr(loc1);
return "0";
}
//Driver Code
int main()
{
int n = 17;
//Function call
cout << decimalToBinary(n);
return 0;
}
//This code is contributed by yashbeersingh42
输出 :
10001
我们可以使用按位运算运算符来完成上述工作。请注意,按位运算运算符的工作速度高于上面使用的算术运算运算符。
C++
// CPP program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
#include
using namespace std;
// Function that convert Decimal to binary
int decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if (k & 1)
cout << "1";
else
cout << "0";
}
}
// driver code
int main()
{
int n = 32;
decToBinary(n);
}
Java
// Java program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
class gfg {
// Function that convert Decimal to binary
public void decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if ((k & 1) > 0)
System.out.print("1");
else
System.out.print("0");
}
}
}
class geek {
// driver code
public static void main(String[] args)
{
gfg g = new gfg();
int n = 32;
g.decToBinary(n);
}
}
// This code is contributed by mits
Python3
# Python3 program to Decimal
# to binary conversion using
# bitwise operator
# Size of an integer is
# assumed to be 32 bits
# Function that convert
# Decimal to binary
def decToBinary(n):
# Size of an integer is
# assumed to be 32 bits
for i in range(31, -1, -1):
k = n >> i;
if (k & 1):
print("1", end = "");
else:
print("0", end = "");
# Driver Code
n = 32;
decToBinary(n);
# This code is contributed by mits
C#
// C# program to Decimal to binary conversion
// using bitwise operator
// Size of an integer is assumed to be 32 bits
using System;
class gfg {
// Function that convert Decimal to binary
public void decToBinary(int n)
{
// Size of an integer is assumed to be 32 bits
for (int i = 31; i >= 0; i--) {
int k = n >> i;
if ((k & 1) > 0)
Console.Write("1");
else
Console.Write("0");
}
}
}
class geek {
// driver code
public static int Main()
{
gfg g = new gfg();
int n = 32;
g.decToBinary(n);
return 0;
}
}
的PHP
= 0; $i--)
{
$k = $n >> $i;
if ($k & 1)
echo "1";
else
echo "0";
}
}
// Driver Code
$n = 32;
decToBinary($n);
// This code is contributed by aj_36
?>
Java脚本
输出 :
00000000000000000000000000100000
感谢ajay0007建议上述解决方案。
也可以在不使用数组的情况下将十进制转换为二进制。
C++
// C++ implementation of the approach
#include
#include
using namespace std;
#define ull unsigned long long int
// Function to return the binary
// equivalent of decimal value N
int decimalToBinary(int N)
{
// To store the binary number
ull B_Number = 0;
int cnt = 0;
while (N != 0) {
int rem = N % 2;
ull c = pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
int main()
{
int N = 17;
cout << decimalToBinary(N);
return 0;
}
Java
// Java implementation of the approach
import java.io.*;
class GFG
{
// Function to return the binary
// equivalent of decimal value N
static int decimalToBinary(int N)
{
// To store the binary number
int B_Number = 0;
int cnt = 0;
while (N != 0)
{
int rem = N % 2;
double c = Math.pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
public static void main (String[] args)
{
int N = 17;
System.out.println (decimalToBinary(N));
}
}
// This code is contribted by ajit.
Python3
# Python3 implementation of the approach
# Function to return the binary
# equivalent of decimal value N
def decimalToBinary(N):
# To store the binary number
B_Number = 0
cnt = 0
while (N != 0):
rem = N % 2
c = pow(10, cnt)
B_Number += rem * c
N //= 2
# Count used to store exponent value
cnt += 1
return B_Number
# Driver code
N = 17
print(decimalToBinary(N))
# This code is contributed by
# SHUBHAMSINGH10
C#
// C# implementation of the approach
using System;
class GFG
{
// Function to return the binary
// equivalent of decimal value N
static int decimalToBinary(int N)
{
// To store the binary number
int B_Number = 0;
int cnt = 0;
while (N != 0)
{
int rem = N % 2;
int c = (int)Math.Pow(10, cnt);
B_Number += rem * c;
N /= 2;
// Count used to store exponent value
cnt++;
}
return B_Number;
}
// Driver code
static public void Main ()
{
int N = 17;
Console.Write(decimalToBinary(N));
}
}
// This code is contributed by Tushil.
Java脚本
输出 :
10001
请注意,此方法类似于本文中讨论的将Binary转换为Decimal的方法。
还有另一种方法可以将任何十进制数转换为其二进制形式。这个想法是使用bitset 。
下面是上述方法的实现。
C++
//C++ program to convert a decimal mumber
//to its binary form.
//including heaader file
#include
using namespace std;
//Function to convert a decimal mumber
//to its binary form
string decimalToBinary(int n)
{
//finding the binary form of the number and
//coneverting it to string.
string s = bitset<64> (n).to_string();
//Finding the first occurance of "1"
//to strip off the leading zeroes.
const auto loc1 = s.find('1');
if(loc1 != string::npos)
return s.substr(loc1);
return "0";
}
//Driver Code
int main()
{
int n = 17;
//Function call
cout << decimalToBinary(n);
return 0;
}
//This code is contributed by yashbeersingh42
输出 :
10001