给定数字N,任务是找到第一个N个中心十六进制数之和。
The first few Centered Hexadecagonal Numbers are 1, 17, 49, 97, 161, 241 …
例子:
Input: N = 3
Output: 67
Explanation:
1, 17 and 49 are the first three centered Hexadecagonal numbers.
Input: N = 5
Output: 325
方法:
- 最初,我们需要创建一个函数,该函数将帮助我们计算第N个中心十六进制数。
- 现在,我们运行一个从1到N的循环,以找到第i个中心十六进制数。
- 将所有以上计算的中心十六进制数相加。
- 最后,显示第一个N中心十六进制数字的总和。
下面是上述方法的实现:
C++
// C++ program to find the sum of the first
// N centred hexadecagonal numbers
#include
using namespace std;
// Centered_Hexadecagonal
// number function
int Centered_Hexadecagonal_num(int n)
{
// Formula to calculate nth
// Centered_Hexadecagonal
// number & return it into
// main function.
return (8 * n * n - 8 * n + 1);
}
// Function to find the sum of the first
// N centered hexadecagonal number
int sum_Centered_Hexadecagonal_num(int n)
{
// Variable to store the sum
int summ = 0;
// Loop to iterate through the
// first N numbers
for(int i = 1; i < n + 1; i++)
{
// Finding the sum
summ += Centered_Hexadecagonal_num(i);
}
return summ;
}
// Driver code
int main()
{
int n = 5;
// Display first Nth
// Centered_Hexadecagonal number
cout << sum_Centered_Hexadecagonal_num(n);
}
// This code is contributed by coder001
Java
// Java program to find the sum of the first
// N centred hexadecagonal numbers
class GFG{
// Centered_Hexadecagonal
// number function
public static int Centered_Hexadecagonal_num(int n)
{
// Formula to calculate nth
// Centered_Hexadecagonal
// number & return it into
// main function.
return (8 * n * n - 8 * n + 1);
}
// Function to find the sum of the first
// N centered hexadecagonal number
public static int sum_Centered_Hexadecagonal_num(int n)
{
// Variable to store the sum
int summ = 0;
// Loop to iterate through the
// first N numbers
for(int i = 1; i < n + 1; i++)
{
// Finding the sum
summ += Centered_Hexadecagonal_num(i);
}
return summ;
}
// Driver Code
public static void main(String[] args)
{
int n = 5;
// Display first Nth
// Centered_Hexadecagonal number
System.out.println(sum_Centered_Hexadecagonal_num(n));
}
}
// This code is contributed by divyeshrabadiya07
Python3
# Python3 program to find the sum of
# the first N centred
# hexadecagonal numbers
# Centered_Hexadecagonal
# number function
def Centered_Hexadecagonal_num(n):
# Formula to calculate
# nth Centered_Hexadecagonal
# number & return it
# into main function.
return (8 * n * n -
8 * n + 1)
# Function to find the
# sum of the first N
# Centered Hexadecagonal
# number
def sum_Centered_Hexadecagonal_num(n) :
# Variable to store the
# sum
summ = 0
# Loop to iterate through the
# first N numbers
for i in range(1, n + 1):
# Find the sum
summ += Centered_Hexadecagonal_num(i)
return summ
# Driver Code
if __name__ == '__main__' :
n = 5
# display first Nth
# Centered_Hexadecagonal number
print(sum_Centered_Hexadecagonal_num(n))
C#
// C# program to find the sum of the first
// N centred hexadecagonal numbers
using System;
class GFG{
// Centered_Hexadecagonal
// number function
public static int Centered_Hexadecagonal_num(int n)
{
// Formula to calculate nth
// Centered_Hexadecagonal
// number & return it into
// main function.
return (8 * n * n - 8 * n + 1);
}
// Function to find the sum of the first
// N centered hexadecagonal number
public static int sum_Centered_Hexadecagonal_num(int n)
{
// Variable to store the sum
int summ = 0;
// Loop to iterate through the
// first N numbers
for(int i = 1; i < n + 1; i++)
{
// Finding the sum
summ += Centered_Hexadecagonal_num(i);
}
return summ;
}
// Driver Code
public static void Main()
{
int n = 5;
// Display first Nth
// Centered_Hexadecagonal number
Console.Write(sum_Centered_Hexadecagonal_num(n));
}
}
// This code is contributed by Code_Mech
Javascript
输出:
325
时间复杂度: O(N)