📅  最后修改于: 2023-12-03 15:31:49.016000             🧑  作者: Mango
When using Spring Save Repository, it is possible to encounter the javax.persistence.EntityNotFoundException error. This error is thrown when the entity being searched for in the repository is not found.
There are several possible causes of this error message, including:
To resolve the javax.persistence.EntityNotFoundException error, follow these steps:
@Repository
public interface MyRepository extends JpaRepository<MyEntity, Long>{
Optional<MyEntity> findBySomeProperty(String someProperty);
}
In the example above, the MyRepository
interface extends JpaRepository
and declares a method for finding an entity by someProperty
. If the entity is not found, the javax.persistence.EntityNotFoundException
error message will be thrown.
To handle this error message, wrap the repository call in a try-catch block as follows:
@Service
public class MyService {
@Autowired
private MyRepository myRepository;
public MyEntity findMyEntityBySomeProperty(String someProperty) {
try {
return myRepository.findBySomeProperty(someProperty)
.orElseThrow(() -> new EntityNotFoundException());
} catch (EntityNotFoundException exception) {
throw new EntityNotFoundException("Could not find MyEntity with property " + someProperty);
}
}
}
By wrapping the repository call in a try-catch block, you can handle the javax.persistence.EntityNotFoundException
error message and provide a more meaningful error message to the caller.
The javax.persistence.EntityNotFoundException error message can be resolved by verifying that the entity being searched for exists in the database, is spelled correctly, is of the correct type, and that the repository is correctly configured and accessible. By wrapping the repository call in a try-catch block, you can handle the error message and provide a more meaningful error message to the caller.