Python3程序将所有零移动到数组末尾| Set-2(使用单次遍历)
给定一个包含n 个数字的数组。问题是将所有 0 移动到数组的末尾,同时保持其他元素的顺序。只需要对数组进行一次遍历。
例子:
Input : arr[] = {1, 2, 0, 0, 0, 3, 6}
Output : 1 2 3 6 0 0 0
Input: arr[] = {0, 1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0, 9}
Output: 1 9 8 4 2 7 6 9 0 0 0 0 0
算法:
moveZerosToEnd(arr, n)
Initialize count = 0
for i = 0 to n-1
if (arr[i] != 0) then
swap(arr[count++], arr[i])
Python3
# Python implementation to move all zeroes at
# the end of array
# function to move all zeroes at
# the end of array
def moveZerosToEnd (arr, n):
# Count of non-zero elements
count = 0;
# Traverse the array. If arr[i] is non-zero, then
# swap the element at index 'count' with the
# element at index 'i'
for i in range(0, n):
if (arr[i] != 0):
arr[count], arr[i] = arr[i], arr[count]
count+=1
# function to print the array elements
def printArray(arr, n):
for i in range(0, n):
print(arr[i],end=" ")
# Driver program to test above
arr = [ 0, 1, 9, 8, 4, 0, 0, 2,
7, 0, 6, 0, 9 ]
n = len(arr)
print("Original array:", end=" ")
printArray(arr, n)
moveZerosToEnd(arr, n)
print("
Modified array: ", end=" ")
printArray(arr, n)
# This code is contributed by
# Smitha Dinesh Semwal
输出:
Original array: 0 1 9 8 4 0 0 2 7 0 6 0 9
Modified array: 1 9 8 4 2 7 6 9 0 0 0 0 0
时间复杂度:O(n)。
辅助空间:O(1)。
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