将所有零移动到数组末尾 | Set-2(使用单次遍历)
给定一个包含n 个数字的数组。问题是将所有 0 移动到数组的末尾,同时保持其他元素的顺序。只需要对数组进行一次遍历。
例子:
Input : arr[] = {1, 2, 0, 0, 0, 3, 6}
Output : 1 2 3 6 0 0 0
Input: arr[] = {0, 1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0, 9}
Output: 1 9 8 4 2 7 6 9 0 0 0 0 0
算法:
moveZerosToEnd(arr, n)
Initialize count = 0
for i = 0 to n-1
if (arr[i] != 0) then
arr[count++]=arr[i]
for i = count to n-1
arr[i] = 0
CPP
// C++ implementation to move all zeroes at
// the end of array
#include
using namespace std;
// function to move all zeroes at
// the end of array
void moveZerosToEnd(int arr[], int n)
{
// Count of non-zero elements
int count = 0;
// Traverse the array. If arr[i] is non-zero, then
// update the value of arr at index count to arr[i]
for (int i = 0; i < n; i++)
if (arr[i] != 0)
arr[count++] = arr[i];
// Update all elements at index >=count with value 0
for (int i = count; i
Java
// Java implementation to move
// all zeroes at the end of array
import java.io.*;
class GFG {
// function to move all zeroes at
// the end of array
static void moveZerosToEnd(int arr[], int n) {
// Count of non-zero elements
int count = 0;
// Traverse the array. If arr[i] is non-zero, then
// update the value of arr at index count to arr[i]
for (int i = 0; i < n; i++)
if (arr[i] != 0)
arr[count++] = arr[i];
// Update all elements at index >=count with value 0
for (int i = count; i
Python3
# Python implementation to move all zeroes at
# the end of array
# function to move all zeroes at
# the end of array
def moveZerosToEnd (arr, n):
# Count of non-zero elements
count = 0;
# Traverse the array. If arr[i] is non-zero, then
# update the value of arr at index count to arr[i]
for i in range(0, n):
if (arr[i] != 0):
arr[count] = arr[i]
count+=1
# Update all elements at index >=count with value 0
for i in range(count, n):
arr[i] = 0
# function to print the array elements
def printArray(arr, n):
for i in range(0, n):
print(arr[i],end=" ")
# Driver program to test above
arr = [ 0, 1, 9, 8, 4, 0, 0, 2,
7, 0, 6, 0, 9 ]
n = len(arr)
print("Original array:", end=" ")
printArray(arr, n)
moveZerosToEnd(arr, n)
print("\nModified array: ", end=" ")
printArray(arr, n)
# This code is contributed by
# Ashutosh Singh
C#
// C# implementation to move
// all zeroes at the end of array
using System;
class GFG {
// function to move all zeroes at
// the end of array
static void moveZerosToEnd(int[] arr, int n)
{
// Count of non-zero elements
int count = 0;
// Traverse the array. If arr[i] is non-zero, then
// update the value of arr at index count to arr[i]
for (int i = 0; i < n; i++)
if (arr[i] != 0)
arr[count++] = arr[i];
// Update all elements at index >=count with value 0
for (int i = count; i
Javascript
输出
Original array: 0 1 9 8 4 0 0 2 7 0 6 0 9
Modified array: 1 9 8 4 2 7 6 9 0 0 0 0 0
时间复杂度:O(n)。
辅助空间:O(1)。