链表 |设置 3(删除节点)
我们在之前关于单链表的文章中讨论了链表介绍和链表插入。
让我们制定问题陈述来理解删除过程。给定一个“键”,删除链表中第一次出现的键。
迭代法:
要从链表中删除节点,我们需要执行以下步骤。
1) 找到要删除的节点的上一个节点。
2)改变上一个节点的next。
3) 待删除节点的空闲内存。
由于链表的每个节点都是在 C 中使用 malloc() 动态分配的,因此我们需要调用 free() 来释放为要删除的节点分配的内存。
C++
// A complete working C++ program to
// demonstrate deletion in singly
// linked list with class
#include
using namespace std;
// A linked list node
class Node{
public:
int data;
Node* next;
};
// Given a reference (pointer to pointer)
// to the head of a list and an int,
// inserts a new node on the front of the
// list.
void push(Node** head_ref, int new_data)
{
Node* new_node = new Node();
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
// Given a reference (pointer to pointer)
// to the head of a list and a key, deletes
// the first occurrence of key in linked list
void deleteNode(Node** head_ref, int key)
{
// Store head node
Node* temp = *head_ref;
Node* prev = NULL;
// If head node itself holds
// the key to be deleted
if (temp != NULL && temp->data == key)
{
*head_ref = temp->next; // Changed head
delete temp; // free old head
return;
}
// Else Search for the key to be deleted,
// keep track of the previous node as we
// need to change 'prev->next' */
else
{
while (temp != NULL && temp->data != key)
{
prev = temp;
temp = temp->next;
}
// If key was not present in linked list
if (temp == NULL)
return;
// Unlink the node from linked list
prev->next = temp->next;
// Free memory
delete temp;
}
}
// This function prints contents of
// linked list starting from the
// given node
void printList(Node* node)
{
while (node != NULL)
{
cout << node->data << " ";
node = node->next;
}
}
// Driver code
int main()
{
// Start with the empty list
Node* head = NULL;
// Add elements in linked list
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
puts("Created Linked List: ");
printList(head);
deleteNode(&head, 1);
puts("\nLinked List after Deletion of 1: ");
printList(head);
return 0;
}
// This code is contributed by ac121102
C
// A complete working C program
// to demonstrate deletion in
// singly linked list
#include
#include
// A linked list node
struct Node {
int data;
struct Node* next;
};
/* Given a reference (pointer to pointer) to the head of a
list and an int, inserts a new node on the front of the
list. */
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node
= (struct Node*)malloc(sizeof(struct Node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
/* Given a reference (pointer to pointer) to the head of a
list and a key, deletes the first occurrence of key in
linked list */
void deleteNode(struct Node** head_ref, int key)
{
// Store head node
struct Node *temp = *head_ref, *prev;
// If head node itself holds the key to be deleted
if (temp != NULL && temp->data == key) {
*head_ref = temp->next; // Changed head
free(temp); // free old head
return;
}
// Search for the key to be deleted, keep track of the
// previous node as we need to change 'prev->next'
while (temp != NULL && temp->data != key) {
prev = temp;
temp = temp->next;
}
// If key was not present in linked list
if (temp == NULL)
return;
// Unlink the node from linked list
prev->next = temp->next;
free(temp); // Free memory
}
// This function prints contents of linked list starting
// from the given node
void printList(struct Node* node)
{
while (node != NULL) {
printf(" %d ", node->data);
node = node->next;
}
}
// Driver code
int main()
{
/* Start with the empty list */
struct Node* head = NULL;
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
puts("Created Linked List: ");
printList(head);
deleteNode(&head, 1);
puts("\nLinked List after Deletion of 1: ");
printList(head);
return 0;
}
Java
// A complete working Java program
// to demonstrate deletion
// in singly linked list
class LinkedList {
Node head; // head of list
/* Linked list Node*/
class Node {
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
/* Given a key, deletes the first
occurrence of key in
* linked list */
void deleteNode(int key)
{
// Store head node
Node temp = head, prev = null;
// If head node itself holds the key to be deleted
if (temp != null && temp.data == key) {
head = temp.next; // Changed head
return;
}
// Search for the key to be deleted, keep track of
// the previous node as we need to change temp.next
while (temp != null && temp.data != key) {
prev = temp;
temp = temp.next;
}
// If key was not present in linked list
if (temp == null)
return;
// Unlink the node from linked list
prev.next = temp.next;
}
/* Inserts a new Node at front of the list. */
public void push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
/* This function prints contents of linked list starting
from the given node */
public void printList()
{
Node tnode = head;
while (tnode != null) {
System.out.print(tnode.data + " ");
tnode = tnode.next;
}
}
/* Driver program to test above functions. Ideally this
function should be in a separate user class. It is kept
here to keep code compact */
public static void main(String[] args)
{
LinkedList llist = new LinkedList();
llist.push(7);
llist.push(1);
llist.push(3);
llist.push(2);
System.out.println("\nCreated Linked list is:");
llist.printList();
llist.deleteNode(1); // Delete node with data 1
System.out.println(
"\nLinked List after Deletion of 1:");
llist.printList();
}
}
Python3
# A complete working Python3 program to
# demonstrate deletion in singly
# linked list with class
# Node class
class Node:
# Constructor to initialize the node object
def __init__(self, data):
self.data = data
self.next = None
class LinkedList:
# Function to initialize head
def __init__(self):
self.head = None
# Function to insert a new node at the beginning
def push(self, new_data):
new_node = Node(new_data)
new_node.next = self.head
self.head = new_node
# Given a reference to the head of a list and a key,
# delete the first occurrence of key in linked list
def deleteNode(self, key):
# Store head node
temp = self.head
# If head node itself holds the key to be deleted
if (temp is not None):
if (temp.data == key):
self.head = temp.next
temp = None
return
# Search for the key to be deleted, keep track of the
# previous node as we need to change 'prev.next'
while(temp is not None):
if temp.data == key:
break
prev = temp
temp = temp.next
# if key was not present in linked list
if(temp == None):
return
# Unlink the node from linked list
prev.next = temp.next
temp = None
# Utility function to print the linked LinkedList
def printList(self):
temp = self.head
while(temp):
print (" %d" %(temp.data)),
temp = temp.next
# Driver program
llist = LinkedList()
llist.push(7)
llist.push(1)
llist.push(3)
llist.push(2)
print ("Created Linked List: ")
llist.printList()
llist.deleteNode(1)
print ("\nLinked List after Deletion of 1:")
llist.printList()
# This code is contributed by Nikhil Kumar Singh (nickzuck_007)
C#
// A complete working C# program
// to demonstrate deletion in
// singly linked list
using System;
class GFG{
// Head of list
Node head;
// Linked list Node
public class Node
{
public int data;
public Node next;
public Node(int d)
{
data = d;
next = null;
}
}
// Given a key, deletes the first
// occurrence of key in linked list
void deleteNode(int key)
{
// Store head node
Node temp = head, prev = null;
// If head node itself holds
// the key to be deleted
if (temp != null &&
temp.data == key)
{
// Changed head
head = temp.next;
return;
}
// Search for the key to be
// deleted, keep track of the
// previous node as we need
// to change temp.next
while (temp != null &&
temp.data != key)
{
prev = temp;
temp = temp.next;
}
// If key was not present
// in linked list
if (temp == null)
return;
// Unlink the node from linked list
prev.next = temp.next;
}
// Inserts a new Node at
// front of the list.
public void Push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
// This function prints contents
// of linked list starting from
// the given node
public void printList()
{
Node tnode = head;
while (tnode != null)
{
Console.Write(tnode.data + " ");
tnode = tnode.next;
}
}
// Driver code
public static void Main(String[] args)
{
GFG llist = new GFG();
llist.Push(7);
llist.Push(1);
llist.Push(3);
llist.Push(2);
Console.WriteLine("\nCreated Linked list is:");
llist.printList();
// Delete node with data 1
llist.deleteNode(1);
Console.WriteLine("\nLinked List after Deletion of 1:");
llist.printList();
}
}
// This code is contributed by Rajput-Ji
Javascript
C++
// C++ program to delete a node in
// singly linked list recursively
#include
using namespace std;
struct node {
int info;
node* link = NULL;
node() {}
node(int a)
: info(a)
{
}
};
/*
Deletes the node containing 'info' part as val and
alter the head of the linked list (recursive method)
*/
void deleteNode(node*& head, int val)
{
// Check if list is empty or we
// reach at the end of the
// list.
if (head == NULL) {
cout << "Element not present in the list\n";
return;
}
// If current node is the node to be deleted
if (head->info == val) {
node* t = head;
head = head->link; // If it's start of the node head
// node points to second node
delete (t); // Else changes previous node's link to
// current node's link
return;
}
deleteNode(head->link, val);
}
// Utility function to add a
// node in the linked list
// Here we are passing head by
// reference thus no need to
// return it to the main function
void push(node*& head, int data)
{
node* newNode = new node(data);
newNode->link = head;
head = newNode;
}
// Utility function to print
// the linked list (recursive
// method)
void print(node* head)
{
// cout<info << ' ';
print(head->link);
}
int main()
{
// Starting with an empty linked list
node* head = NULL;
// Adds new element at the
// beginning of the list
push(head, 10);
push(head, 12);
push(head, 14);
push(head, 15);
// original list
print(head);
deleteNode(head, 20); // Call to delete function
print(head); // 20 is not present thus no change in the
// list
deleteNode(head, 10);
print(head);
deleteNode(head, 14);
print(head);
return 0;
}
输出
Created Linked List:
2 3 1 7
Linked List after Deletion of 1:
2 3 7
递归方法:
要递归删除链表的节点,我们需要执行以下步骤。
1.我们传递node*(节点指针)作为对函数的引用(如node* &head)
2.现在由于当前节点指针是从前一个节点的下一个(通过引用传递)派生的,所以现在如果当前节点指针的值发生变化,则前一个下一个节点的值也会发生变化,这是删除节点时所需的操作(即指向前一个节点的下一个当前节点的(包含键)下一个)。
3.找到包含给定值的节点。
4.存储此节点以稍后使用 free()函数解除分配。
5.更改此节点指针,使其指向它的下一个,并通过执行此前一个节点的下一个也得到正确链接。
下面是上述方法的实现。
C++
// C++ program to delete a node in
// singly linked list recursively
#include
using namespace std;
struct node {
int info;
node* link = NULL;
node() {}
node(int a)
: info(a)
{
}
};
/*
Deletes the node containing 'info' part as val and
alter the head of the linked list (recursive method)
*/
void deleteNode(node*& head, int val)
{
// Check if list is empty or we
// reach at the end of the
// list.
if (head == NULL) {
cout << "Element not present in the list\n";
return;
}
// If current node is the node to be deleted
if (head->info == val) {
node* t = head;
head = head->link; // If it's start of the node head
// node points to second node
delete (t); // Else changes previous node's link to
// current node's link
return;
}
deleteNode(head->link, val);
}
// Utility function to add a
// node in the linked list
// Here we are passing head by
// reference thus no need to
// return it to the main function
void push(node*& head, int data)
{
node* newNode = new node(data);
newNode->link = head;
head = newNode;
}
// Utility function to print
// the linked list (recursive
// method)
void print(node* head)
{
// cout<info << ' ';
print(head->link);
}
int main()
{
// Starting with an empty linked list
node* head = NULL;
// Adds new element at the
// beginning of the list
push(head, 10);
push(head, 12);
push(head, 14);
push(head, 15);
// original list
print(head);
deleteNode(head, 20); // Call to delete function
print(head); // 20 is not present thus no change in the
// list
deleteNode(head, 10);
print(head);
deleteNode(head, 14);
print(head);
return 0;
}
Element not present in the list
15 14 12 10
15 14 12
15 12
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