用于删除链表中节点的 C 程序
我们在之前关于单链表的文章中讨论了链表介绍和链表插入。
让我们制定问题陈述以了解删除过程。给定一个“键”,删除链表中该键的第一次出现。
迭代方法:
要从链表中删除一个节点,我们需要执行以下步骤。
1)找到要删除的节点的前一个节点。
2)改变前一个节点的下一个。
3) 为要删除的节点释放内存。
由于链表的每个节点都是使用 C 中的 malloc() 动态分配的,因此我们需要调用 free() 来释放为要删除的节点分配的内存。
C
// A complete working C program
// to demonstrate deletion in
// singly linked list
#include
#include
// A linked list node
struct Node {
int data;
struct Node* next;
};
/* Given a reference (pointer to pointer) to the head of a
list and an int, inserts a new node on the front of the
list. */
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node
= (struct Node*)malloc(sizeof(struct Node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
/* Given a reference (pointer to pointer) to the head of a
list and a key, deletes the first occurrence of key in
linked list */
void deleteNode(struct Node** head_ref, int key)
{
// Store head node
struct Node *temp = *head_ref, *prev;
// If head node itself holds the key to be deleted
if (temp != NULL && temp->data == key) {
*head_ref = temp->next; // Changed head
free(temp); // free old head
return;
}
// Search for the key to be deleted, keep track of the
// previous node as we need to change 'prev->next'
while (temp != NULL && temp->data != key) {
prev = temp;
temp = temp->next;
}
// If key was not present in linked list
if (temp == NULL)
return;
// Unlink the node from linked list
prev->next = temp->next;
free(temp); // Free memory
}
// This function prints contents of linked list starting
// from the given node
void printList(struct Node* node)
{
while (node != NULL) {
printf(" %d ", node->data);
node = node->next;
}
}
// Driver code
int main()
{
/* Start with the empty list */
struct Node* head = NULL;
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
puts("Created Linked List: ");
printList(head);
deleteNode(&head, 1);
puts("
Linked List after Deletion of 1: ");
printList(head);
return 0;
}
输出:
Created Linked List:
2 3 1 7
Linked List after Deletion of 1:
2 3 7
请参阅链表上的完整文章 |设置 3(删除节点)了解更多详情!