交换矩阵中第一列和最后一列的元素

给定一个 4 x 4 矩阵，任务是交换第一列和最后一列的元素并显示结果矩阵。
例子：

方法很简单，我们可以简单地交换矩阵的第一列和最后一列的元素，以获得所需的矩阵作为输出。
下面是上述方法的实现：

C++

// C++ code to swap the element of first
// and last column and display the result
#include 
using namespace std;
 
#define n 4
 
void interchangeFirstLast(int m[][n])
{
    // swapping of element between first
    // and last columns
    for (int i = 0; i < n; i++) {
        int t = m[i][0];
        m[i][0] = m[i][n - 1];
        m[i][n - 1] = t;
    }
}
 
// Driver function
int main()
{
    // input in the array
    int m[n][n] = { { 8, 9, 7, 6 },
                    { 4, 7, 6, 5 },
                    { 3, 2, 1, 8 },
                    { 9, 9, 7, 7 } };
 
    interchangeFirstLast(m);
 
    // printing the interchanged matrix
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++)
            cout << m[i][j] << " ";
        cout << endl;
    }
}

Java

// Java code to swap the element of first
// and last column and display the result
 
import java.io.*;
 
class GFG {
    
static int n = 4;
 
static void interchangeFirstLast(int m[][])
{
    int cols = n;
 
    // swapping of element between first
    // and last columns
    for (int i = 0; i < n; i++) {
        int t = m[i][0];
        m[i][0] = m[i][n - 1];
        m[i][n - 1] = t;
    }
}
 
// Driver function
 
    public static void main (String[] args) {
            // input in the array
    int m[][] = { { 8, 9, 7, 6 },
                    { 4, 7, 6, 5 },
                    { 3, 2, 1, 8 },
                    { 9, 9, 7, 7 } };
 
    interchangeFirstLast(m);
 
    // printing the interchanged matrix
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++)
            System.out.print(m[i][j] + " ");
            System.out.println();
    }
    }
}
// This code is contributed by inder_verma

Python 3

# Python3 code to swap the element of
# first and last column and display
# the result
   
def interchangeFirstLast(mat, n, m):
    rows = n
       
    # swapping of element between
    # first and last columns
    for i in range(n):
            t = mat[i][0];
            mat[i][0] = mat[i][n-1];
            mat[i][n-1] = t;
   
# Driver Program
mat = [[8, 9, 7, 6],
       [4, 7, 6, 5],
       [3, 2, 1, 8],
       [9, 9, 7, 7]]
   
n = 4
m = 4
interchangeFirstLast(mat, n, m)
   
# printing the interchanged matrix
for i in range(n):
    for j in range(m):
        print(mat[i][j], end = " ")
    print("\n")

C#

// C# code to swap the element of first
// and last column and display the result
using System;
 
class GFG
{
     
static int n = 4;
 
static void interchangeFirstLast(int[, ] m)
{
    int cols = n;
 
    // swapping of element between first
    // and last columns
    for (int i = 0; i < n; i++)
    {
        int t = m[i, 0];
        m[i, 0] = m[i, n - 1];
        m[i, n - 1] = t;
    }
}
 
// Driver Code
public static void Main ()
{
// input in the array
int[,] m = { { 8, 9, 7, 6 },
                { 4, 7, 6, 5 },
                { 3, 2, 1, 8 },
                { 9, 9, 7, 7 } };
 
interchangeFirstLast(m);
 
// printing the interchanged matrix
for (int i = 0; i < n; i++)
{
    for (int j = 0; j < n; j++)
        Console.Write(m[i, j] + " ");
        Console.WriteLine();
}
}
}
 
// This code is contributed
// by Akanksha Rai

PHP

Javascript

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