检查给定的字符串是否可以分成四个不同的字符串
给定一个字符串，任务是检查我们是否可以将其拆分为 4 个字符串，使得每个字符串都非空且彼此不同。
例子：
Input : str[] = "geeksforgeeks"
Output : Yes
"geeks", "for", "gee", "ks" are four
distinct strings that can form from
given string.
Input : str[] = "aaabb"
Output : No观察字符串的长度是否大于等于10，那么每次可以拆分成四部分。假设长度为10，则可以制作长度为1、2、3、4的字符串。
对于长度小于 10 的字符串，我们可以使用蛮力，即遍历所有可能的分割字符串的方法并检查每一种。
If length is more than 10
return true
Else (If length is less than 10)
Use Brute Force method to check
if we can break it in four distinct
strings.下面是上述想法的实现。
C++
// C++ program to check if we can break a string
// into four distinct strings.
#include
using namespace std;
// Return if the given string can be split or not.
bool check(string s)
{
// We can always break a string of size 10 or
// more into four distinct strings.
if (s.size() >= 10)
return true;
// Brute Force
for (int i =1; i < s.size(); i++)
{
for (int j = i + 1; j < s.size(); j++)
{
for (int k = j + 1; k < s.size(); k++)
{
// Making 4 string from the given string
string s1 = s.substr(0, i);
string s2 = s.substr(i, j - i);
string s3 = s.substr(j, k - j);
string s4 = s.substr(k, s.size() - k);
// Checking if they are distinct or not.
if (s1 != s2 && s1 != s3 && s1 != s4 &&
s2 != s3 && s2 != s4 && s3 != s4)
return true;
}
}
}
return false;
}
// Driven Program
int main()
{
string str = "aaabb";
(check(str))? (cout << "Yes" << endl):
(cout << "No" << endl);
return 0;
} Java
// Java program to check if we can break a string
// into four distinct strings.
class GFG
{
// Return true if both strings are equal
public static boolean strcheck(String s1, String s2)
{
if (s1.compareTo(s2) != 0)
return false;
return true;
}
// Return if the given string can be split or not.
public static boolean check(String s)
{
if (s.length() >= 10)
return true;
// Brute Force
for (int i = 1; i < s.length(); i++)
{
for (int j = i + 1; j < s.length(); j++)
{
for (int k = j + 1; k < s.length(); k++)
{
// Making 4 string from the given string
String s1 = "", s2 = "", s3 = "", s4 = "";
try
{
s1 = s.substring(0, i);
s2 = s.substring(i, j - i);
s3 = s.substring(j, k - j);
s4 = s.substring(k, s.length() - k);
}
catch (StringIndexOutOfBoundsException e) {
}
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
// Driver code
public static void main(String[] args)
{
String str = "aaabb";
if (check(str))
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by
// sanjeev2552Python3
# Python3 program to check if we can
# break a into four distinct strings.
# Return if the given string can be
# split or not.
def check(s):
# We can always break a of size 10 or
# more into four distinct strings.
if (len(s) >= 10):
return True
# Brute Force
for i in range(1, len(s)):
for j in range(i + 1, len(s)):
for k in range(j + 1, len(s)):
# Making 4 from the given
s1 = s[0:i]
s2 = s[i:j - i]
s3 = s[j: k - j]
s4 = s[k: len(s) - k]
# Checking if they are distinct or not.
if (s1 != s2 and s1 != s3 and s1 != s4 and
s2 != s3 and s2 != s4 and s3 != s4):
return True
return False
# Driver Code
if __name__ == '__main__':
str = "aaabb"
print("Yes") if(check(str)) else print("NO")
# This code is contributed
# by SHUBHAMSINGH10C#
// C# program to check if we can break a string
// into four distinct strings.
using System;
class GFG
{
// Return true if both strings are equal
public static Boolean strcheck(String s1,
String s2)
{
if (s1.CompareTo(s2) != 0)
return false;
return true;
}
// Return if the given string
// can be split or not.
public static Boolean check(String s)
{
if (s.Length >= 10)
return true;
// Brute Force
for (int i = 1; i < s.Length; i++)
{
for (int j = i + 1; j < s.Length; j++)
{
for (int k = j + 1; k < s.Length; k++)
{
// Making 4 string from the given string
String s1 = "", s2 = "",
s3 = "", s4 = "";
try
{
s1 = s.Substring(0, i);
s2 = s.Substring(i, j - i);
s3 = s.Substring(j, k - j);
s4 = s.Substring(k, s.Length - k);
}
catch (Exception e) {
}
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
// Driver code
public static void Main(String[] args)
{
String str = "aaabb";
if (check(str))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by Princi SinghJavascript
输出：
No