给定数字N,任务是找到该系列的第N个项:
3, 5, 21, 51, 95, ….
例子:
Input: N = 4
Output: 51
Explanation:
Nth term = (7 * pow(N, 2) - 19 * N + 15)
= (7 * pow(4, 2) - 19 * 4 + 15)
= 51
Input: N = 10
Output: 525
方法:
给定级数的N个项可以概括为:
[Tex] [/ Tex]
下面是上述方法的实现:
C++
// CPP program to find N-th term of the series:
// 3, 5, 21, 51, 95,...
#include
#include
using namespace std;
// calculate Nth term of series
int getNthTerm(long long int N)
{
// Return Nth term
return (7 * pow(N, 2) - 19 * N + 15);
}
// driver code
int main()
{
// declaration of number of terms
long long int N = 4;
// Get the Nth term
cout << getNthTerm(N);
return 0;
}
Java
// Java program to find N-th term of the series:
// 3, 5, 21, 51, 95,...
import java.util.*;
class solution
{
static long getNthTerm(long N)
{
// Return Nth term
return (7 *(int) Math.pow(N, 2) - 19 * N + 15);
}
//Driver program
public static void main(String arr[])
{
// declaration of number of terms
long N = 4;
// Get the Nth term
System.out.println(getNthTerm(N));
}
}
Python3
# Python3 program to find N-th term
# of the series:
# 3, 5, 21, 51, 95,...
# calculate Nth term of series
def getNthTerm(N):
#Return Nth term
return (7 * pow(N, 2) - 19 * N + 15)
#Driver code
if __name__=='__main__':
#declaration of number of terms
N = 4
#Get the Nth term
print(getNthTerm(N))
#this code is contributed by Shashank_Sharma
C#
// C# program to find
// N-th term of the series:
// 3, 5, 21, 51, 95,...
using System;
class GFG
{
static long getNthTerm(long N)
{
// Return Nth term
return (7 *(int) Math.Pow(N, 2) -
19 * N + 15);
}
// Driver Code
static public void Main ()
{
// declaration of number
// of terms
long N = 4;
// Get the Nth term
Console.Write(getNthTerm(N));
}
}
// This code is contributed by Raj
PHP
Javascript
输出:
51
时间复杂度: O(1)