用于计算文本文件中键值对出现次数的Python程序

给定一个键值对的文本文件。任务是计算文件中键值对的出现次数。

例子：

Input File:
Coin:H
Coin:T
Coin:H
Coin:H
Coin:H
Coin:T
Coin:H
Coin:T
Coin:H
Coin:H

Output:
The count of coin:h is 7
The count of coin:t is 3

Input File:
geeks:G
for:F
geeks:G
geeks:G
geek:H
for:F
geek:H

Output:
The count of geeks:g is 3
The count of for:f is 2
The count of geek:h is 2

方法很简单。维护另一个字典（比如 d），它将存储文件的每个键值对的出现次数。将文本文件的键值对作为键存储在字典中。现在遍历文件的键值对。如果字典中存在该对，则将该对的值加一，否则插入该对并将其值设置为 1。

下面是实现。

文本文件：

# Python program to count the
# occurrences of key-value pair
# in the text file
  
  
# opening text file
f = open("file.txt", "r")
d = dict()
  
for res in f:
    # removing new line and extra
    # space characters
    res = res.strip()
  
    # changing ase to prevent matching
    # errors
    res = res.lower()
  
    # separating key-value pairs
    lines = res.split()
  
    for line in lines:
  
        if line in d:
  
            # If the key-value pair
            # is present in d then 
            # increment its value by one
            d[line] = d[line]+1
        else:
  
            # Insert the key-value pair
            # in the dictionary and sets
            # its value to one
            d[line] = 1
  
f.close()
  
# Printing Result
for key in list(d.keys()):
    print("The count of {} is {}".format(key,d[key]))

输出 ：