Python – 将字符串列表转换为键值列表字典

给定一个字符串，将其转换为键值列表字典，其中键为第一个单词，其余单词为值列表。

Input : test_list = [“gfg is best for geeks”, “CS is best subject”]
Output : {‘gfg’: [‘is’, ‘best’, ‘for’, ‘geeks’], ‘CS’: [‘is’, ‘best’, ‘subject’]}
Explanation : 1st elements are paired with respective rest of words as list.

Input : test_list = [“gfg is best for geeks”]
Output : {‘gfg’: [‘is’, ‘best’, ‘for’, ‘geeks’]}
Explanation : 1st elements are paired with respective rest of words as list.

方法 #1：使用 split() + 循环

在此，我们对每个字符串进行迭代，然后使用 split() 对字符串进行拆分，将第一个元素指定为键并将其他元素打包到列表中，使用 *运算符并创建键值列表对。

Python3

# Python3 code to demonstrate working of 
# Convert String List to Key-Value List dictionary
# Using split() + loop
  
# initializing list
test_list = ["gfg is best for geeks", "I love gfg", "CS is best subject"]
  
# printing string
print("The original list : " + str(test_list))
  
  
res = dict()
for sub in test_list:
      
    # split() for key 
    # packing value list
    key, *val = sub.split()
    res[key] = val
  
# printing results 
print("The key values List dictionary : " + str(res))

输出

The original list : ['gfg is best for geeks', 'I love gfg', 'CS is best subject']
The key values List dictionary : {'gfg': ['is', 'best', 'for', 'geeks'], 'I': ['love', 'gfg'], 'CS': ['is', 'best', 'subject']}

方法#2：使用 split() + 字典理解

这是解决此问题的类似方法。在这里，字典理解被用来解决这个问题。

Python3

# Python3 code to demonstrate working of 
# Convert String List to Key-Value List dictionary
# Using split() + dictionary comprehension
  
# initializing list
test_list = ["gfg is best for geeks", "I love gfg", "CS is best subject"]
  
# printing string
print("The original list : " + str(test_list))
  
# using dictionary comprehension to solve this problem
res = {sub[0] : sub[1:] for sub in (ele.split() for ele in test_list)}
  
# printing results 
print("The key values List dictionary : " + str(res))

输出

The original list : ['gfg is best for geeks', 'I love gfg', 'CS is best subject']
The key values List dictionary : {'gfg': ['is', 'best', 'for', 'geeks'], 'I': ['love', 'gfg'], 'CS': ['is', 'best', 'subject']}