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📜  使用链表对给定的字符数组进行排序

📅  最后修改于: 2022-05-13 01:56:07.180000             🧑  作者: Mango

使用链表对给定的字符数组进行排序

给定一个包含N个小写英文字母的数组arr[] ,任务是使用链表对该数组arr[]进行排序。

例子:

方法:要解决这个问题,首先从字符数组创建链表。形成链表后,使用冒泡排序对其进行排序。

下面是上述方法的实现:

C++
#include 
using namespace std;
  
// Structure for a node
struct Node {
    int data;
    Node* next;
} Node;
  
// Function to swap the nodes
struct Node* swap(struct Node* ptr1, struct Node* ptr2)
{
    struct Node* tmp = ptr2->next;
    ptr2->next = ptr1;
    ptr1->next = tmp;
    return ptr2;
}
  
// Function to sort the list
int bubbleSort(struct Node** head, int count)
{
    struct Node** h;
    int i, j, swapped;
  
    for (i = 0; i <= count; i++) {
  
        h = head;
        swapped = 0;
  
        for (j = 0; j < count - i - 1; j++) {
  
            struct Node* p1 = *h;
            struct Node* p2 = p1->next;
  
            if (p1->data > p2->data) {
  
                // Update the link after swapping
                *h = swap(p1, p2);
                swapped = 1;
            }
  
            h = &(*h)->next;
        }
  
        // Break if the loop ended
        // without any swap
        if (swapped == 0)
            break;
    }
}
  
// Function to print the list
void printList(struct Node* n)
{
    while (n != NULL) {
        cout << char(n->data) << " -> ";
        n = n->next;
    }
    cout << endl;
}
  
// Function to insert a struct Node
// at the end of a linked list
void insert(struct Node** head, int data)
{
    struct Node* ptr = new struct Node();
  
    ptr->data = data;
    ptr->next = NULL;
    if (*head == NULL) {
        *head = ptr;
    }
    else {
        struct Node* ptr1 = *head;
        while (ptr1->next != NULL) {
            ptr1 = ptr1->next;
        }
        ptr1->next = ptr;
    }
}
  
// Driver Code
int main()
{
    int arr[] = { 'b', 'b', 'c', 'c', 'd', 'e',
                  'f', 'b', 'b', 'a', 'a' };
    int list_size, i;
  
    // start with empty linked list
    struct Node* start = NULL;
    list_size = sizeof(arr) / sizeof(arr[0]);
  
    // Create linked list from the array arr[]
    for (i = 0; i < list_size; i++)
        insert(&start, arr[i]);
  
    // sort the linked list
    bubbleSort(&start, list_size);
  
    // Print list after sorting
    printList(start);
  
    return 0;
}


输出
a -> a -> b -> b -> b -> b -> c -> c -> d -> e -> f -> 

时间复杂度: O(N 2 )