📜  寻找平方根极客' - 任何代码示例

📅  最后修改于: 2022-03-11 14:58:59.553000             🧑  作者: Mango

代码示例1
# THIS METHOD IS CALLED NEWTON-RAPHSON METHOD
n = 23049234
sq =1          # you can take it as any positive number
i = 0
for i in range(n):    
    temp = sq
    sq = (sq + n/sq)/2
    i += 1
    if temp  == sq:  # as the value starts repeating we have reached the final precison
        break
print(sq)