📜  Python中的 numpy.iscomplexobj()

📅  最后修改于: 2022-05-13 01:55:40.094000             🧑  作者: Mango

Python中的 numpy.iscomplexobj()

numpy.iscomplexobj(array) :此逻辑函数有助于检查数组或复数数组的复数类型。即使虚部等于 0,它也被认为是一个复杂对象。

参数 :

array    : [array_like]Input array or object whose elements, we need to test.

返回 :

True, if the input array has a complex element; otherwise False 

代码 1:

Python
# Python program explaining
# iscomplexobj() function
import numpy as np
 
in_array = [1, 3, 5, 4]
print ("Input array : ", in_array)
 
output_value = np.iscomplexobj(in_array)
print ("\nIs complex : ", output_value)


Python
# Python Program illustrating
# numpy.iscomplexobj() method
import numpy as geek
   
# Returns True/False value for each element
a = geek.arange(20).reshape(5, 4)
print("Is complex : \n", geek.iscomplexobj(a))
   
# Returns True/False value as ans
# because we have mentioned dtpe in the beginning
b = geek.arange(20).reshape(5, 4).dtype = complex
                 
print("\n",b)
print("\nIs complex : ", geek.iscomplexobj(b))
  
  
b = [[1j],
     [3]]
print("\nIs complex : \n", geek.iscomplexobj(b))


输出 :

Input array :  [1, 3, 5, 4]

Is complex :  False

代码 2:

Python

# Python Program illustrating
# numpy.iscomplexobj() method
import numpy as geek
   
# Returns True/False value for each element
a = geek.arange(20).reshape(5, 4)
print("Is complex : \n", geek.iscomplexobj(a))
   
# Returns True/False value as ans
# because we have mentioned dtpe in the beginning
b = geek.arange(20).reshape(5, 4).dtype = complex
                 
print("\n",b)
print("\nIs complex : ", geek.iscomplexobj(b))
  
  
b = [[1j],
     [3]]
print("\nIs complex : \n", geek.iscomplexobj(b))

输出 :

Is complex : 
 False

 class 'complex'

Is complex :  False

Is complex : 
 True

参考 :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.iscomplexobj.html#numpy.iscomplexobj