📅  最后修改于: 2022-03-11 15:04:38.535000             🧑  作者: Mango
/*The logic behind the function is to copy and place the ending part of string
along with the deliminator '\0' to the position from where you want the
"no_of_char" number of characters removed*/
void delchar(char *string,int starting_pos, int no_of_char)
{
if (( starting_pos + no_of_char - 1 ) <= strlen(x) )
{
strcpy(&x[starting_pos-1],&x[starting_pos + no_of_char-1]);
puts(x);
}
}