将两个二进制数相乘的Python程序

给定两个二进制数，任务是编写一个Python程序来将两个数相乘。

例子：

firstnumber = 110
secondnumber = 10
Multiplication Result = 1100

我们可以使用Python以两种方式将两个二进制数相乘，它们是：

1. 使用 bin() 函数和
2. 不使用预定义函数

方法 1：使用 bin 函数

现在，让我们使用预定义函数编写一个程序：

Python3

firstnumber = 110
secondnumber = 10
  
firstnumber = str(firstnumber)
secondnumber = str(secondnumber)
  
Multiplication = int(firstnumber, 2) * int(secondnumber, 2)
binaryMul = bin(Multiplication)
  
print("\nResult = " + binaryMul)

输出：

Result = 0b1100

方法二：不使用任何预定义函数

我们还可以在不使用任何预定义函数或用户定义函数的情况下将任意两个二进制数相乘。

Python

def binaryProduct(binaryOne, binaryTwo):
    i = 0
    remainder = 0
    sum = []
    binaryProd = 0
  
    # if firstBinary number or second Binary number is not
    # zero then calculate the product of two Binary numbers
    while binaryOne != 0 or binaryTwo != 0:
        sum.insert(i, (((binaryOne % 10) + (binaryTwo % 10) + remainder) % 2))
        remainder = int(((binaryOne % 10) + (binaryTwo % 10) + remainder) / 2)
        binaryOne = int(binaryOne/10)
        binaryTwo = int(binaryTwo/10)
        i = i+1
  
    # if remainder value is not equal to
    # zero then insert the digit to sum array
    if remainder != 0:
        sum.insert(i, remainder)
        i = i+1
    i = i-1
    while i >= 0:
        binaryProd = (binaryProd * 10) + sum[i]
        i = i-1
    return binaryProd
  
  
binaryMultiply = 0
factor = 1
firstBinary = 110
  
secondBinary = 10
  
# Now check if secondbinary number have any
# digit or not and continue multiplying
# each digit of the second binary number with
# first binary number till the last digit of
# second binary number
while secondBinary != 0:
    digit = secondBinary % 10
    if digit == 1:
        firstBinary = firstBinary * factor
        binaryMultiply = binaryProduct(firstBinary, binaryMultiply)
    else:
        firstBinary = firstBinary * factor
    secondBinary = int(secondBinary/10)
    factor = 10
print("\nMultiplication Result = " + str(binaryMultiply))

输出：

Multiplication Result = 1100