Python - 删除交替的连续重复

给定元素列表，删除交替的连续重复元素。

Input : test_list = [5, 5, 5, 5, 6, 6]
Output : [5, 5, 6]
Explanation : Alternate occ. of 5 and 6 are removed.

Input : test_list = [5, 5, 5, 5]
Output : [5, 5]
Explanation : Alternate occ. of 5 are removed.

方法：使用循环+remove()

上述功能的组合可以用来解决这个问题。在此，我们迭代每个元素并使用附加的先前元素变量来跟踪替代标准。使用 remove() 执行删除。

Python3

# Python3 code to demonstrate working of 
# Remove alternate consecutive duplicates
# Using loop + remove()
  
# initializing lists
test_list = [5, 5, 5, 5, 6, 6, 8, 3, 3, 8]
  
# printing original list
print("The original list : " + str(test_list))
  
# Using loop to iterate through elements
# element to keep track
temp = test_list[0]
count = 0
org_list = test_list
idx = 0
while(1):
      
    # break when idx greater than size
    if idx >= len(org_list):
        break
      
    # check for alternates 
    if count % 2 and temp == test_list[idx]:
        test_list.remove(test_list[idx])
        idx = idx - 1
        count += 1
        temp = test_list[idx]
    else:
          
        # keeping track of alternate index increment
        # and assignment
        if temp != test_list[idx]:
            count = 1
            temp = test_list[idx]
        else :
            count += 1
    idx = idx + 1
  
# printing result 
print("List after alternate duplicates removal : " + str(test_list))

输出

The original list : [5, 5, 5, 5, 6, 6, 8, 3, 3, 8]
List after alternate duplicates removal : [5, 5, 6, 8, 3, 8]