Python程序将浮点十进制数转换为八进制数

Python不支持任何内置函数来轻松地将浮点十进制数转换为八进制表示。让我们手动执行此操作。方法：要将有小数部分的十进制数转换为八进制，首先将整数部分转换为八进制形式，然后将小数部分转换为八进制形式，最后将两者结合得到最终答案。
对于整数部分，继续将数字除以 8 并记下余数，直到被除数小于 8 并将所有余数复制在一起。
对于小数部分，继续将小数部分乘以 8，直到并且除非我们得到 0 作为小数部分。第一次相乘后，记下整数部分，然后再次将新值的小数部分乘以 8，并继续这样做，直到达到完美数字。

Above steps can be written as :
7(base 10) = 7(base 8) and .16(base 10) = .1217(base 8)

Now, to get the octal of the decimal number 7.16, merge the two octal results. (7)10 = (7)8

(0.16)10 = (0.1217...)8 So, (7.16)10 = (7.1217...)8 or, (7.16)10 = (7.1217)8 (approx. value)

编程需要懂一点英语

下面是实现：

# Python3 program to demonstrate
# octal type conversion
  
# Function returns the octal representation
# of the value passed as parameters. 'number'
# is floating point decimal number and 'places'
# is the number of decimal places
def float_octal(number, places = 3):
  
    # split() separates whole number and decimal 
    # part and stores it in two separate variables
    whole, dec = str(number).split(".")
  
    # Convert both whole number and decimal  
    # part from string type to integer type
    whole = int(whole)
    dec = int (dec)
  
    # Convert the whole number part to it's
    # respective octal form and remove the
    # "0o" from it.
    res = oct(whole).lstrip("0o") + "."
  
    # Iterate the number of times we want
    # the number of decimal places to be
    for x in range(places):
  
        # Multiply the decimal value by 8 and separate 
        # the whole number part and decimal part
        whole, dec = str((decimal_converter(dec)) * 8).split(".")
  
        # Convert the decimal part
        # to integer again
        dec = int(dec)
  
        # keep adding the integer parts 
        # received to the result variable
        res += whole
  
    return res
  
# Function converts the value passed as
# parameter to it's respective decimal
# representation
def decimal_converter(num):
    while num > 1:
        num /= 10
    return num
  
# Driver Code
  
# Take the user input for 
# the floating point number
n = input("Enter your floating point value : \n")
  
# Take user input for the number of decimal 
# places user would like the result as
p = int(input("Enter the number of decimal places of the result : \n"))
  
print(float_octal(n, places = p))

输出：

Enter your floating point value :
7.16

Enter the number of decimal places of the result :
10

7.1217273146

Enter your floating point value :
7.1234

Enter the number of decimal places of the result : 
5

7.07713