Python中的 numpy.setxor1d()函数

numpy.setxor1d()函数找到两个数组的异或集，并返回仅在一个（不是两个）输入数组中的排序后的唯一值。

Syntax : numpy.setxor1d(arr1, arr2, assume_unique = False)

Parameters :
arr1, arr2 : [array_like] Input arrays.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.

Return : [ndarray] Sorted 1D array of unique values that are in only one of the input arrays.

代码#1：

# Python program explaining
# numpy.setxor1d() function
    
# importing numpy as geek 
import numpy as geek 
   
arr1 = [1, 2, 3, 4]
arr2 = [2, 4, 6, 8]
   
gfg = geek.setxor1d(arr1, arr2)
   
print (gfg)

输出 ：

[1 3 6 8]

代码#2：

# Python program explaining
# numpy.setxor1d() function
    
# importing numpy as geek 
import numpy as geek 
   
arr1 = [1, 2, 3, 4, 5]
arr2 = [-2, -1, 0, 1, 2]
   
gfg = geek.setxor1d(arr1, arr2)
   
print (gfg)

输出 ：

[-2 -1  0  3  4  5]