Python – 连接元组列表中的后部元素

给定元组列表，连接后部元素。

Input : test_list = [(1, 2, “Gfg”), (“Best”, )]
Output : Gfg Best
Explanation : Last elements are joined.

Input : test_list = [(1, 2, “Gfg”)]
Output : Gfg
Explanation : Last elements are joined.

方法 #1：使用列表理解 + join()

在此，我们使用“-1”作为索引检查最后一个元素，并使用 join() 执行连接，列表推导用于迭代每个元组。

Python3

# Python3 code to demonstrate working of 
# Concatenate Rear elements in Tuple List
# Using join() + list comprehension
  
# initializing list
test_list = [(1, 2, "Gfg"), (4, "is"), ("Best", )]
  
# printing original list
print("The original list is : " + str(test_list))
  
# "-1" is used for access
res = " ".join([sub[-1] for sub in test_list]) 
  
# printing result 
print("The Concatenated result : " + str(res))

输出

The original list is : [(1, 2, 'Gfg'), (4, 'is'), ('Best', )]
The Concatenated result : Gfg is Best

方法 #2：使用 map() + itemgetter() + join()

在此，我们使用 itemgetter(-1) 执行获取最后一个元素的任务，而 map() 用于获取所有最后一个元素，使用 join() 进行连接。

Python3

# Python3 code to demonstrate working of 
# Concatenate Rear elements in Tuple List
# Using map() + itemgetter() + join()
from operator import itemgetter
  
# initializing list
test_list = [(1, 2, "Gfg"), (4, "is"), ("Best", )]
  
# printing original list
print("The original list is : " + str(test_list))
  
# "-1" is used for access
# map() to get all elements 
res = " ".join(list(map(itemgetter(-1), test_list))) 
  
# printing result 
print("The Concatenated result : " + str(res))

输出

The original list is : [(1, 2, 'Gfg'), (4, 'is'), ('Best', )]
The Concatenated result : Gfg is Best