📅  最后修改于: 2022-03-11 15:02:51.448000             🧑  作者: Mango
const mySet1 = new Set()
mySet1.add(1) // Set [ 1 ]
mySet1.add(5) // Set [ 1, 5 ]
mySet1.add(5) // Set [ 1, 5 ]
mySet1.add('some text') // Set [ 1, 5, 'some text' ]
const o = {a: 1, b: 2}
mySet1.add(o)
mySet1.add({a: 1, b: 2}) // o is referencing a different object, so this is okay
mySet1.has(1) // true
mySet1.has(3) // false, since 3 has not been added to the set
mySet1.has(5) // true
mySet1.has(Math.sqrt(25)) // true
mySet1.has('Some Text'.toLowerCase()) // true
mySet1.has(o) // true
mySet1.size // 5
mySet1.delete(5) // removes 5 from the set
mySet1.has(5) // false, 5 has been removed
mySet1.size // 4, since we just removed one value
console.log(mySet1)
// logs Set(4) [ 1, "some text", {…}, {…} ] in Firefox
// logs Set(4) { 1, "some text", {…}, {…} } in Chrome