Python| SymPy Permutation.atoms() 方法

Permutation.atoms() ：atoms()是一个 sympy Python库函数，它返回排列中存在的所有元素。

Syntax : sympy.combinatorics.permutations.Permutation.atoms()

Return : elements of the argumented permutation.

代码 #1：atoms() 示例

# Python code explaining
# SymPy.Permutation.atoms()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.atoms() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - atoms form : ", a.atoms())
print ("Permutation b - atoms form : ", b.atoms())

输出 ：

Permutation a – atoms form : {0, 1, 2, 3}
Permutation b – atoms form : {0, 1, 2, 3, 4, 5}

代码 #2：atoms() 示例– 2D 排列

# Python code explaining
# SymPy.Permutation.atoms()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.atoms() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - atoms form : ", a.atoms())

输出 ：

Permutation a – ascents form : [1, 2, 4]