Python| SymPy Permutation.cycles() 方法

Permutation.cycles() ：cycles()是一个 sympy Python库函数，它返回排列中存在的循环数。这也包括单例。

Syntax :
sympy.combinatorics.permutations.Permutation.cycles()

Return :
number of cycles present in the permutation

代码 #1：cycles() 示例

# Python code explaining
# SymPy.Permutation.cycles()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.cycles() method 
  
# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])
  
b = Permutation([3, 1, 2, 5, 4, 0])
  
  
print ("Permutation a - cycles form : ", a.cycles)
print ("Permutation b - cycles form : ", b.cycles)

输出 ：

Permutation a – cycles form : 2
Permutation b – cycles form : 4

代码 #2：cycles() 示例– 2D 排列

# Python code explaining
# SymPy.Permutation.cycles()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from 
# sympy.combinatorics.permutations.Permutation.cycles() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
# SELF COMMUTATING    
print ("Permutation a - cycles form : ", a.cycles)

输出 ：

Permutation a – cycles form : 1