Python - 由列表中的最大邻居替换

给定一个列表，任务是编写一个Python程序来替换前一个和下一个元素之间的最大邻居。

Input : test_list = [5, 4, 2, 5, 8, 2, 1, 9], 
Output : [5, 5, 5, 8, 8, 8, 9, 9] 
Explanation : 4 is having 5 and 2 as neighbours, replaced by 5 as greater than 2.

Input : test_list = [5, 4, 2, 5], 
Output : [5, 5, 5, 5] 
Explanation : 4 is having 5 and 2 as neighbours, replaced by 5 as greater than 2. 
 

方法一：使用循环+链条件语句

在这里，我们使用循环遍历列表中的所有元素，并使用条件检查邻居是否有更大的元素，然后被替换。

Python3

# Python3 code to demonstrate working of
# Replacing by Greatest Neighbour
# Using loop + chain conditional statements
  
# initializing list
test_list = [5, 4, 2, 5, 8, 2, 1, 9]
  
# printing original list
print("The original list is : " + str(test_list))
  
for idx in range(1, len(test_list) - 1):
  
    # replacing by greater Neighbour
    test_list[idx] = test_list[idx - 1] \
    if test_list[idx - 1] > test_list[idx + 1] \
    else test_list[idx + 1]
  
# printing result
print("The elements after replacing : " + str(test_list))

输出：

The original list is : [5, 4, 2, 5, 8, 2, 1, 9]
The elements after replacing : [5, 5, 5, 8, 8, 8, 9, 9]

方法 2：使用 max() + 循环。

在这里，我们使用 max() 获得相邻元素中的最大元素。循环用于遍历元素。

蟒蛇3

# Python3 code to demonstrate working of 
# Replacing by Greatest Neighbour
# Using max() + loop
  
# initializing list
test_list = [5, 4, 2, 5, 8, 2, 1, 9]
  
# printing original list
print("The original list is : " + str(test_list))
  
for idx in range(1, len(test_list) - 1):
      
    # using max() to get maximum of Neighbours
    test_list[idx] = max(test_list[idx - 1], test_list[idx + 1])
          
# printing result 
print("The elements after replacing : " + str(test_list))

输出：

The original list is : [5, 4, 2, 5, 8, 2, 1, 9]
The elements after replacing : [5, 5, 5, 8, 8, 8, 9, 9]