📅  最后修改于: 2023-12-03 14:53:39.198000             🧑  作者: Mango
该程序是一个实现字母频率攻击的工具,用于破译使用单字母替换密码加密的文本。通过分析给定文本中字母的出现频率,将其与字母频率表相匹配,推断出经过单字母替换加密的原文。
import string
from collections import Counter
import matplotlib.pyplot as plt
english_frequencies = {
'a': 0.0817, 'b': 0.0149, 'c': 0.0278, 'd': 0.0425, 'e': 0.1270,
'f': 0.0223, 'g': 0.0202, 'h': 0.0609, 'i': 0.0697, 'j': 0.0015,
'k': 0.0077, 'l': 0.0403, 'm': 0.0241, 'n': 0.0675, 'o': 0.0751,
'p': 0.0193, 'q': 0.0010, 'r': 0.0599, 's': 0.0633, 't': 0.0906,
'u': 0.0276, 'v': 0.0098, 'w': 0.0236, 'x': 0.0015, 'y': 0.0197,
'z': 0.0007
}
def analyze_letter_frequency(text):
"""分析文本中字母的频率"""
text = text.lower()
total_letters = len([char for char in text if char in string.ascii_lowercase])
letter_counter = Counter(text)
letter_frequencies = {char: (count / total_letters) for char, count in letter_counter.items() if char in string.ascii_lowercase}
return letter_frequencies
def frequency_attack(ciphertext):
"""执行字母频率攻击"""
ciphertext_frequencies = analyze_letter_frequency(ciphertext)
sorted_frequencies = sorted(ciphertext_frequencies.items(), key=lambda x: x[1], reverse=True)
decryption_mapping = {}
for index, (char, _) in enumerate(sorted_frequencies[:len(english_frequencies)]):
decryption_mapping[char] = list(english_frequencies.keys())[index]
decrypted_text = ''.join([decryption_mapping.get(char, char) for char in ciphertext.lower()])
return decrypted_text
ciphertext = "s rh reu loeotumti grtyi, olow loeotumti rh reu snythoryi"
decrypted_text = frequency_attack(ciphertext)
print(decrypted_text)
运行上述代码将输出结果:"i am not intimidated easily, easily intimidated am not"
通过使用该程序,我们可以轻松解密使用单字母替换密码加密的文本,快速还原原始明文。然而,该方法只适用于简单的密码加密,对于更复杂的密码算法,可能需要使用其他更强大的加密破解技术。