Python中的 numpy.nanargmax()

numpy.nanargmax()函数返回忽略 NaN 的特定轴中数组的最大元素的索引。
如果切片仅包含 NaN 和 Inf，则结果不可信。

句法：

numpy.nanargmax(array, axis = None) 

参数 ：

array : Input array to work on 
axis  : [int, optional]Along a specified axis like 0 or 1

返回 ：

Array of indices into the array with same shape as array.shape
 with the dimension along axis removed.

代码 1：

Python

# Python Program illustrating
# working of nanargmax()
 
import numpy as geek
 
# Working on 1D array
array = [geek.nan, 4, 2, 3, 1]
print("INPUT ARRAY 1 : \n", array)
 
array2 = geek.array([[geek.nan, 4], [1, 3]])
 
# returning Indices of the max element
# as per the indices ingnoring NaN
print("\nIndices of max in array1 : ", geek.nanargmax(array))
 
# Working on 2D array
print("\nINPUT ARRAY 2 : \n", array2)
print("\nIndices of max in array2 : ", geek.nanargmax(array2))
 
print("\nIndices at axis 1 of array2 : ", geek.nanargmax(array2, axis = 1))

输出 ：

INPUT ARRAY 1 : 
 [nan, 4, 2, 3, 1]

Indices of max in array1 :  1

INPUT ARRAY 2 : 
 [[ nan   4.]
 [  1.   3.]]

Indices of max in array2 :  1

Indices at axis 1 of array2 :  [1 1]

代码 2：比较 argmax 和 nanargmax 的工作

Python

# Python Program illustrating
# working of nanargmax()
 
import numpy as geek
 
# Working on 2D array
array = ( [[ 8, 13, 5, 0],
           [ 16, geek.nan, 5, 3],
           [geek.nan, 7, 15, 15],
           [3, 11, 4, 12]])
print("INPUT ARRAY : \n", array)
 
# returning Indices of the max element
# as per the indices
 
'''  
   [[ 8 13  5  0]
   [ 16  2  5  3]
   [10  7 15 15]
   [ 3 11  4 12]]
     ^  ^  ^  ^
      
'''
 
print("\nIndices of max using argmax : ", geek.argmax(array, axis = 0))
print("\nIndices of max using nanargmax :  : ", geek.nanargmax(array, axis = 0))

输出 ：

INPUT ARRAY : 
 [[8, 13, 5, 0], [16, nan, 5, 3], [nan, 7, 15, 15], [3, 11, 4, 12]]

Indices of max using argmax :  [2 1 2 2]

Indices of max using nanargmax :  :  [1 0 2 2]

参考 ：
https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.nanargmax.html#numpy.nanargmax

笔记 ：
这些代码不会在在线 IDE 上运行。因此，请在您的系统上运行它们以探索其工作原理。