最大除数，将所有自然数除以范围[L，R]

给定两个整数L和R ，任务是找到将所有自然数都除以[L，R]的最大除数。
例子：

Input: L = 3, R = 12 
Output: 1
Input: L = 24, R = 24 
Output: 24 
 

方法：对于一系列连续的整数元素，有两种情况：

• 如果L = R，则答案将为L。
• 如果L 则此范围内的所有连续自然数均为互质数。因此， 1是唯一可以划分范围内所有元素的数字。

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
 
// Function to return the greatest divisor that
// divides all the natural numbers in the range [l, r]
int find_greatest_divisor(int l, int r)
{
    if (l == r)
        return l;
 
    return 1;
}
 
// Driver Code
int main()
{
    int l = 2, r = 12;
 
    cout << find_greatest_divisor(l, r);
}

Java

// Java implementation of the approach
 
class GFG {
 
// Function to return the greatest divisor that
// divides all the natural numbers in the range [l, r]
    static int find_greatest_divisor(int l, int r) {
        if (l == r) {
            return l;
        }
 
        return 1;
    }
 
// Driver Code
    public static void main(String[] args) {
        int l = 2, r = 12;
 
        System.out.println(find_greatest_divisor(l, r));
    }
}
// This code is contributed by PrinciRaj1992

Python3

# Python3 implementation of the approach
 
# Function to return the greatest divisor that
# divides all the natural numbers in the range [l, r]
def find_greatest_divisor(l, r):
 
    if (l == r):
        return l;
 
    return 1;
 
 
# Driver Code
 
l = 2;
r = 12;
 
print(find_greatest_divisor(l, r));
 
#This code is contributed by Shivi_Aggarwal

C#

// C# implementation of the approach
using System;
 
class GFG {
 
    // Function to return the greatest divisor that
    // divides all the natural numbers in the range [l, r]
    static int find_greatest_divisor(int l, int r) {
        if (l == r) {
            return l;
        }
 
        return 1;
    }
 
    // Driver Code
    public static void Main() {
        int l = 2,  r = 12 ;
 
        Console.WriteLine(find_greatest_divisor(l, r));
    }
    // This code is contributed by Ryuga
 
}

Javascript

 
// Javascript implementation of the approach
 
// Function to return the greatest
// divisor that divides all the natural
// numbers in the range [l, r]
function find_greatest_divisor(l, r)
{
    if (l == r)
        return l;
 
    return 1;
}
 
// Driver Code
let l = 2;
let r = 12;
 
document.write( find_greatest_divisor(l, r));
 
// This code is contributed
// by bobby
 

输出：

1

时间复杂度： O(1)