这是用于Cognizant技术解决方案面试的能力准备的模型介绍文件。这份安置文件将涵盖在CTS招聘活动中提出的才能问题,并且还将严格遵循在CTS面试中提出的问题模式。建议解决以下每个问题,以增加清除CTS面试的机会。
- 找到(100!)^ 100除以23时的余数?
a)3
b)2
c)1
d)0Answer: d) 0
Solution:
We know that 100! = 100 * 99 * 98 * … * 23 * 22 * 21 * … * 3 * 2 * 1
So when this equation is divided by 23, the remainder is 0. - 一根管子可以比另一根管子快三倍地充满一个桶。如果两条管道在一起可以在36分钟内将桶装满,那么较慢的管道就可以将桶装满:
a)144分钟。
b)81分钟。
c)108分钟。
d)192分钟。Answer: a) 144 minutes.
Solution:
Let us assume that the slower pipe can fill the bucket in x minutes.
So the faster tap can feel the bucket in x/3 minutes.
According to the question,
Therefore,
1/x+1/(x/3)
1/x + 3/x = 1/36
=> x = 144 minutes. - 当前的阿曼速度为15 km / hr,当前的速度为2.5 km / hr。阿曼逆流而上的速度是多少?
a)8.5公里/小时
b)9公里/小时
c)10公里/小时
d)12.5公里/小时Answer: c) 10 km/hr
Solution:
So Aman’s rate in still water = (15 – 2.5) = 12.5 km/hr.
and Aman’s rate against the current = (12.5 – 2.5) km/hr = 10 km/hr. - 一所学校的数学,物理和生物学的席位比例为5:7:8。提议将这些席位分别增加40%,50%和75%。增加席位的比例是多少?
a)6:7:8
b)2:3:4
c)6:8:9
d)以上都不是Answer: b) 2:3:4
Solution:
Let the ratios of division be = 5x:7x:8x
There is an increase of 40%, 50% and 75% respectively.
Therefore, applying the % over the ratio we get, 7x:21x/2:14x
So, this is the required ratio.
= 14x : 21x: 28x
= 2 : 3 : 4 - 空心铁管长21厘米,外径为8厘米。如果管道的厚度为1厘米,铁的重量为8 g / cm3,则管道的重量为:
a)3.6公斤
b)3.696公斤
c)36公斤
d)36.9公斤Answer: b) 3.696 kg
Solution:
Given the external diameter = 8 cm. Therefore, the radius = 4 cm.
The thickness = 1 cm. Therefore the internal radius = 4 – 1 = 3 cm
The volume of the iron = pi * (R^2 – r^2) * length
= 22/7 * [(4^2) – (3^2)] * 21 cubic-cm
= 462 cubic-cm
Therefore, the weight of iron = 462 * 8 gm = 3.696 kg - 罗希特(Rohit)的父亲比罗希特(Rohit)大三倍。 8年后,他将是Rohit年龄的两倍半。再过8年,他将成为罗希特(Rohit)的年龄几次?
a)2次
b)2.5次
c)2.75次
d)3次。Answer: a) 2 times
Solution:
Let Rohit present age be x years
Therefore father’s age is x + 3x = 4x years
According to the question,
4x + 8 = 5/2(x + 8)
=> 3x = 24
=> x = 8
So the answer is: (4x + 16) / (x + 16) = 48/24 = 2 - 水龙头可以在6小时内装满水桶。将一半的水桶装满后,再打开三个类似的水龙头。完全充满水桶需要多少时间?
a)3小时45分钟
b)3小时15分钟
c)4小时15分钟
d)4小时45分钟Answer: a) 3 hrs 45 min
Solution:
Time is taken by one tap to fill half the bucket = 3 hours
So the part filled 4 taps in one hour = 4 * (1/6) = 2/3 of the bucket.
Therefore, the remaining part is = (1 – 1/2) = 1/2
Proportinally = 2/3 : 1/2 :: 1 : x
=> x = 3/4 hours = 45 minutes. So the total time = 3 hrs 45 minutes. - 在静止水中以15 km / hr的速度行驶的船舶向下游30 km行驶,并在总共4小时30分钟内返回。溪流的速度是多少公里/小时?
a)4
b)6
c)5
d)10Answer: c) 5
Solution:
Let the speed of the stream be x km/hr.
Therfore the, speed of downstream = (15 + x) km/hr,
and speed of upstream = (15 – x) km/hr.
According to the question,
30/(15 + x) + 30/(15 – x) = 9/2
or, 900/(225 – x^2) = 9/2
or, 9x^2 = 225
or, x^2 = 25
or, x = 5 km/hr. - 在60升的混合物中,牛奶与水的比例为2:1。如果该比率为1:2,那么还需要多少水?
a)60升
b)50升
c)40升
d)30升Answer: a) 60 litres
Solution:
From the given ratio we can deduce the quantity of milk as = 60 * (2/3) = 40 lit
and the quantity of water = 60 – 40 = 20 lit
The new ratio must be 1:2
Let the quantity of water to be added be x lit.
Then milk:water = 40 / (20 + x)
This should be equal to = 1/2
=> 20 + x = 80
or, x = 60 - 大厅长15 m,宽12 m。如果地板和天花板的面积之和等于四堵墙的面积之和,则大厅的体积为:
a)720
b)1200
c)900
d)1800Answer: b) 1200
Solution:
According to the question,
2(15 + 12)*h = 2(15 * 12)
=> h = (180/27) = 20/3 meter
Therefore, the volume = l * b * h = (15 * 12 * 20/3) cubic-meter = 1200 (answer)