给定一个数组,找到数组中所有对之和的异或。
例子:
Input : arr[] = {1, 2, 3}
Output : 0
(1 + 1) ^ (1 + 2) ^ (1 + 3) ^ (2 + 1) ^ (2 + 2) ^
(2 + 3) ^ (3 + 1) ^ (3 + 2) ^ (3 + 3) = 0
Input : arr[] = {1, 2, 3, 4}
Output : 8
一个幼稚的方法是一个一个地考虑所有对,然后一个接一个地计算它们的XOR。
C++
// CPP program to find XOR of pair
// sums.
#include
using namespace std;
int xorPairSum(int ar[], int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
sum = sum ^ (ar[i] + ar[j]);
return sum;
}
// Driver code
int main()
{
int arr[] = { 1, 2, 3 };
int n = sizeof(arr)/sizeof(arr[0]);
cout << xorPairSum(arr, n);
return 0;
}
Java
// Java program to find XOR of pair sums.
import java.io.*;
class GFG {
// method to find XOR of pair sums
static int xorPairSum(int ar[], int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
sum = sum ^ (ar[i] + ar[j]);
return sum;
}
// Driver code
public static void main (String[] args)
{
int arr[] = {1, 2, 3};
int n = arr.length;
System.out.print( xorPairSum(arr, n));
}
}
// This code is contributed by chandan_jnu.
Python3
# Python program to find
# XOR of pair sums.
def xor_pair_sum(ar, n):
total = 0
for i in range(n):
for j in range(n):
total = total ^ (ar[i] + ar[j])
return total
# Driver program to test the above function
if __name__ == "__main__":
data = [1, 2, 3]
print(xor_pair_sum(data, len(data)))
# This code is contributed
# by Kanav Malhotra
C#
// C# program to find
// XOR of pair sums.
using System;
class GFG
{
static int xorPairSum(int []ar,
int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
sum = sum ^ (ar[i] + ar[j]);
return sum;
}
// Driver code
static public void Main(String []args)
{
int []arr = { 1, 2, 3 };
int n = arr.Length;
Console.WriteLine(xorPairSum(arr, n));
}
}
// This code is contributed
// by Arnab Kundu
PHP
Javascript
C++
// CPP program to find XOR of pair
// sums.
#include
using namespace std;
int xorPairSum(int ar[], int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2*sum;
}
// Driver code
int main()
{
int arr[] = { 1, 2, 3 };
int n = sizeof(arr)/sizeof(arr[0]);
cout << xorPairSum(arr, n);
return 0;
}
Java
// Java program to find
// XOR of pair sums.
class GFG
{
static int xorPairSum(int ar[],
int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2 * sum;
}
// Driver code
public static void main(String args[])
{
int arr[] = { 1, 2, 3 };
int n = arr.length;
System.out.println( xorPairSum(arr, n));
}
}
// This code is contributed
// by Arnab Kundu
Python3
# Python3 program to find
# XOR of pair sums.
def xor_pair_sum(ar, n):
total = 0
for i in range(n):
total = total ^ ar[i]
return 2 * total
# Driver program to test the above function
if __name__ == "__main__":
data = [1, 2, 3]
print(xor_pair_sum(data, len(data)))
# This code is contributed
# by Kanav Malhotra
C#
// C# program to find
// XOR of pair sums.
using System;
class GFG
{
static int xorPairSum(int []ar,
int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2 * sum;
}
// Driver code
static public void Main(String []args)
{
int []arr = { 1, 2, 3 };
int n = arr.Length;
Console.WriteLine( xorPairSum(arr, n));
}
}
// This code is contributed
// by Arnab Kundu
PHP
Javascript
输出:
0
时间复杂度: O(N 2 )
一个有效的解决方案基于XOR属性。我们只需计算每个元素的XOR,然后将其乘以2。
C++
// CPP program to find XOR of pair
// sums.
#include
using namespace std;
int xorPairSum(int ar[], int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2*sum;
}
// Driver code
int main()
{
int arr[] = { 1, 2, 3 };
int n = sizeof(arr)/sizeof(arr[0]);
cout << xorPairSum(arr, n);
return 0;
}
Java
// Java program to find
// XOR of pair sums.
class GFG
{
static int xorPairSum(int ar[],
int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2 * sum;
}
// Driver code
public static void main(String args[])
{
int arr[] = { 1, 2, 3 };
int n = arr.length;
System.out.println( xorPairSum(arr, n));
}
}
// This code is contributed
// by Arnab Kundu
Python3
# Python3 program to find
# XOR of pair sums.
def xor_pair_sum(ar, n):
total = 0
for i in range(n):
total = total ^ ar[i]
return 2 * total
# Driver program to test the above function
if __name__ == "__main__":
data = [1, 2, 3]
print(xor_pair_sum(data, len(data)))
# This code is contributed
# by Kanav Malhotra
C#
// C# program to find
// XOR of pair sums.
using System;
class GFG
{
static int xorPairSum(int []ar,
int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
sum = sum ^ ar[i];
return 2 * sum;
}
// Driver code
static public void Main(String []args)
{
int []arr = { 1, 2, 3 };
int n = arr.Length;
Console.WriteLine( xorPairSum(arr, n));
}
}
// This code is contributed
// by Arnab Kundu
的PHP
Java脚本
输出:
0
时间复杂度: O(N)