C / C++中的strrchr()函数找到字符串字符的最后一次出现。它返回一个指向字符串最后一次出现的指针。终止的空字符被视为C字符串的一部分。因此,还可以定位它以检索到字符串末尾的指针。它在cstring头文件中定义。
句法 :
const char* strrchr( const char* str, int ch )
or
char* strrchr( char* str, int ch )
参数:该函数采用两个强制性参数,如下所述:
- str:指定要搜索的以空终止的字符串的指针。
- ch:指定要搜索的字符。
返回值:该函数返回一个指针,指向ch的字符串中的最后一个位置,如果通道被发现。如果未找到,则返回空指针。
下面的程序说明了上述函数:
程序1:
// C++ program to illustrate
// the strrchr() function
#include
using namespace std;
int main()
{
// Storing it in string array
char string[] = "Geeks for Geeks";
// The character we've to search for
char character = 'k';
// Storing in a pointer ptr
char* ptr = strrchr(string, character);
// ptr-string gives the index location
if (ptr)
cout << "Last position of " << character
<< " in " << string << " is " << ptr - string;
// If the character we're searching is not present in the array
else
cout << character << " is not present "
<< string << endl;
return 0;
}
输出:
Last position of k in Geeks for Geeks is 13
程式2:
// C++ program to illustrate
// the strrchr() function
#include
using namespace std;
int main()
{
// Storing it in string array
char string[] = "Geeks for Geeks";
char* ptr;
// The character we've to search for
char character = 'z';
// Storing in a pointer ptr
ptr = strrchr(string, character);
// ptr-string gives the index location
if (ptr)
cout << "Last position of " << character
<< " in " << string << " is " << ptr - string;
// If the character we're searching
// is not present in the array
else
cout << character << " is not present in "
<< string << endl;
return 0;
}
输出:
z is not present in Geeks for Geeks
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