< type_traits >头文件中提供了C++ STL的std :: is_trivially_destructible模板。 C++ STL的std :: is_trivially_denstructible模板用于检查T是否为普通可破坏类型。如果T是普通可破坏类型,则它返回布尔值true,否则返回false。
头文件:
#include
模板类别:
template
struct is_trivially_destructible;
句法:
std::is_trivially_destructible::value
参数:模板std :: is_trivially_destructible接受单个参数T(Trait类),以检查T是否为普通可破坏类型。
返回值:该模板返回一个布尔变量,如下所示:
- 正确:如果类型T是可轻易破坏的类型。
- False:如果类型T不是可轻易破坏的类型。
下面的程序说明了C / C++中的std :: is_trivially_destructible模板:
程序1:
// C++ program to illustrate
// std::is_trivially_destructible
#include
#include
using namespace std;
// Declare structures
struct Y {
// Constructor
Y(int, int){};
};
struct X {
// Destructor
~X() noexcept(false)
{
}
};
struct Z {
~Z() = default;
};
// Declare classes
class A {
virtual void fn() {}
};
// Driver Code
int main()
{
cout << boolalpha;
// Check if int is trivially
// destructable or not
cout << "int: "
<< is_trivially_destructible::value
<< endl;
// Check if struct X is trivially
// destructable or not
cout << "struct X: "
<< is_trivially_destructible::value
<< endl;
// Check if struct Y is trivially
// destructable or not
cout << "struct Y: "
<< is_trivially_destructible::value
<< endl;
// Check if struct Z is trivially
// destructable or not
cout << "struct Z: "
<< is_trivially_destructible::value
<< endl;
// Check if class A is trivially
// destructable or not
cout << "class A: "
<< is_trivially_destructible::value
<< endl;
// Check if constructor Y(int, int) is
// trivially destructable or not
cout << "Constructor Y(int, int): "
<< is_trivially_destructible::value
<< endl;
return 0;
}
输出:
int: true
struct X: false
struct Y: true
struct Z: true
class A: true
Constructor Y(int, int): false
参考: http://www.cplusplus.com/reference/type_traits/is_trivially_destructible/
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。要完成从学习语言到DS Algo等的更多准备工作,请参阅“完整面试准备课程” 。