📅  最后修改于: 2020-10-15 04:49:06             🧑  作者: Mango
在此程序中,我们需要从给定的单链列表中删除重复的节点。
原始清单:
删除重复节点后的列表:
在上面的列表中,节点2重复三次,节点1重复两次。当前节点将指向头,索引将指向当前节点。开始遍历列表,直到找到重复项,即当前数据等于索引数据。在上面的示例中,第一个副本位于位置4。将电流分配给另一个节点temp。将temp的下一个节点与索引的下一个节点连接。删除指向重复节点的索引。此过程将继续进行,直到删除所有重复项。
#Represent a node of the singly linked list
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class RemoveDuplicate:
#Represent the head and tail of the singly linked list
def __init__(self):
self.head = None;
self.tail = None;
#addNode() will add a new node to the list
def addNode(self, data):
#Create a new node
newNode = Node(data);
#Checks if the list is empty
if(self.head == None):
#If list is empty, both head and tail will point to new node
self.head = newNode;
self.tail = newNode;
else:
#newNode will be added after tail such that tail's next will point to newNode
self.tail.next = newNode;
#newNode will become new tail of the list
self.tail = newNode;
#removeDuplicate() will remove duplicate nodes from the list
def removeDuplicate(self):
#Node current will point to head
current = self.head;
index = None;
temp = None;
if(self.head == None):
return;
else:
while(current != None):
#Node temp will point to previous node to index.
temp = current;
#Index will point to node next to current
index = current.next;
while(index != None):
#If current node's data is equal to index node's data
if(current.data == index.data):
#Here, index node is pointing to the node which is duplicate of current node
#Skips the duplicate node by pointing to next node
temp.next = index.next;
else:
#Temp will point to previous node of index.
temp = index;
index = index.next;
current = current.next;
#display() will display all the nodes present in the list
def display(self):
#Node current will point to head
current = self.head;
if(self.head == None):
print("List is empty");
return;
while(current != None):
#Prints each node by incrementing pointer
print(current.data);
current = current.next;
sList = RemoveDuplicate();
#Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(2);
sList.addNode(2);
sList.addNode(4);
sList.addNode(1);
print("Originals list: ");
sList.display();
#Removes duplicate nodes
sList.removeDuplicate();
print("List after removing duplicates: ");
sList.display();
输出:
Originals list:
1 2 3 2 2 4 1
List after removing duplicates:
1 2 3 4
#include
//Represent a node of the singly linked list
struct node{
int data;
struct node *next;
};
//Represent the head and tail of the singly linked list
struct node *head, *tail = NULL;
//addNode() will add a new node to the list
void addNode(int data) {
//Create a new node
struct node *newNode = (struct node*)malloc(sizeof(struct node));
newNode->data = data;
newNode->next = NULL;
//Checks if the list is empty
if(head == NULL) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail->next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//removeDuplicate() will remove duplicate nodes from the list
void removeDuplicate() {
//Node current will point to head
struct node *current = head, *index = NULL, *temp = NULL;
if(head == NULL) {
return;
}
else {
while(current != NULL){
//Node temp will point to previous node to index.
temp = current;
//Index will point to node next to current
index = current->next;
while(index != NULL) {
//If current node's data is equal to index node's data
if(current->data == index->data) {
//Here, index node is pointing to the node which is duplicate of current node
//Skips the duplicate node by pointing to next node
temp->next = index->next;
}
else {
//Temp will point to previous node of index.
temp = index;
}
index = index->next;
}
current = current->next;
}
}
}
//display() will display all the nodes present in the list
void display() {
//Node current will point to head
struct node *current = head;
if(head == NULL) {
printf("List is empty \n");
return;
}
while(current != NULL) {
//Prints each node by incrementing pointer
printf("%d ", current->data);
current = current->next;
}
printf("\n");
}
int main()
{
//Adds data to the list
addNode(1);
addNode(2);
addNode(3);
addNode(2);
addNode(2);
addNode(4);
addNode(1);
printf("Originals list: \n");
display();
//Removes duplicate nodes
removeDuplicate();
printf("List after removing duplicates: \n");
display();
return 0;
}
输出:
Originals list:
1 2 3 2 2 4 1
List after removing duplicates:
1 2 3 4
public class RemoveDuplicate {
//Represent a node of the singly linked list
class Node{
int data;
Node next;
public Node(int data) {
this.data = data;
this.next = null;
}
}
//Represent the head and tail of the singly linked list
public Node head = null;
public Node tail = null;
//addNode() will add a new node to the list
public void addNode(int data) {
//Create a new node
Node newNode = new Node(data);
//Checks if the list is empty
if(head == null) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//removeDuplicate() will remove duplicate nodes from the list
public void removeDuplicate() {
//Node current will point to head
Node current = head, index = null, temp = null;
if(head == null) {
return;
}
else {
while(current != null){
//Node temp will point to previous node to index.
temp = current;
//Index will point to node next to current
index = current.next;
while(index != null) {
//If current node's data is equal to index node's data
if(current.data == index.data) {
//Here, index node is pointing to the node which is duplicate of current node
//Skips the duplicate node by pointing to next node
temp.next = index.next;
}
else {
//Temp will point to previous node of index.
temp = index;
}
index = index.next;
}
current = current.next;
}
}
}
//display() will display all the nodes present in the list
public void display() {
//Node current will point to head
Node current = head;
if(head == null) {
System.out.println("List is empty");
return;
}
while(current != null) {
//Prints each node by incrementing pointer
System.out.print(current.data + " ");
current = current.next;
}
System.out.println();
}
public static void main(String[] args) {
RemoveDuplicate sList = new RemoveDuplicate();
//Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(2);
sList.addNode(2);
sList.addNode(4);
sList.addNode(1);
System.out.println("Originals list: ");
sList.display();
//Removes duplicate nodes
sList.removeDuplicate();
System.out.println("List after removing duplicates: ");
sList.display();
}
}
输出:
Originals list:
1 2 3 2 2 4 1
List after removing duplicates:
1 2 3 4
using System;
public class CreateList
{
//Represent a node of the singly linked list
public class Node{
public T data;
public Node next;
public Node(T value) {
data = value;
next = null;
}
}
public class RemoveDuplicate{
//Represent the head and tail of the singly linked list
public Node head = null;
public Node tail = null;
//addNode() will add a new node to the list
public void addNode(T data) {
//Create a new node
Node newNode = new Node(data);
//Checks if the list is empty
if(head == null) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//removeDuplicate() will remove duplicate nodes from the list
public void removeDuplicate() {
//Node current will point to head
Node current = head, index = null, temp = null;
if(head == null) {
return;
}
else {
while(current != null){
//Node temp will point to previous node to index.
temp = current;
//Index will point to node next to current
index = current.next;
while(index != null) {
//If current node's data is equal to index node's data
if(current.data.Equals(index.data)) {
//Here, index node is pointing to the node which is duplicate of current node
//Skips the duplicate node by pointing to next node
temp.next = index.next;
}
else {
//Temp will point to previous node of index.
temp = index;
}
index = index.next;
}
current = current.next;
}
}
}
//display() will display all the nodes present in the list
public void display() {
//Node current will point to head
Node current = head;
if(head == null) {
Console.WriteLine("List is empty");
return;
}
while(current != null) {
//Prints each node by incrementing pointer
Console.Write(current.data + " ");
current = current.next;
}
Console.WriteLine();
}
}
public static void Main()
{
RemoveDuplicate sList = new RemoveDuplicate();
//Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(2);
sList.addNode(2);
sList.addNode(4);
sList.addNode(1);
Console.WriteLine("Originals list: ");
sList.display();
//Removes duplicate nodes
sList.removeDuplicate();
Console.WriteLine("List after removing duplicates: ");
sList.display();
}
}
输出:
Originals list:
1 2 3 2 2 4 1
List after removing duplicates:
1 2 3 4
data = $data;
$this->next = NULL;
}
}
class RemoveDuplicate{
//Represent the head and tail of the singly linked list
public $head;
public $tail;
function __construct(){
$this->head = NULL;
$this->tail = NULL;
}
//addNode() will add a new node to the list
function addNode($data) {
//Create a new node
$newNode = new Node($data);
//Checks if the list is empty
if($this->head == NULL) {
//If list is empty, both head and tail will point to new node
$this->head = $newNode;
$this->tail = $newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
$this->tail->next = $newNode;
//newNode will become new tail of the list
$this->tail = $newNode;
}
}
//removeDuplicate() will remove duplicate nodes from the list
function removeDuplicate() {
//Node current will point to head
$current = $this->head;
$index = null;
$temp = null;
if($this->head == null) {
return;
}
else {
while($current != null){
//Node temp will point to previous node to index.
$temp = $current;
//Index will point to node next to current
$index = $current->next;
while($index != null) {
//If current node's data is equal to index node's data
if($current->data == $index->data) {
//Here, index node is pointing to the node which is duplicate of current node
//Skips the duplicate node by pointing to next node
$temp->next = $index->next;
}
else {
//Temp will point to previous node of index.
$temp = $index;
}
$index = $index->next;
}
$current = $current->next;
}
}
}
//display() will display all the nodes present in the list
function display() {
//Node current will point to head
$current = $this->head;
if($this->head == NULL) {
print("List is empty
");
return;
}
while($current != NULL) {
//Prints each node by incrementing pointer
print($current->data . " ");
$current = $current->next;
}
print("
");
}
}
$sList = new RemoveDuplicate();
//Adds data to the list
$sList->addNode(1);
$sList->addNode(2);
$sList->addNode(3);
$sList->addNode(2);
$sList->addNode(2);
$sList->addNode(4);
$sList->addNode(1);
print("Originals list:
");
$sList->display();
//Removes duplicate nodes
$sList->removeDuplicate();
print("List after removing duplicates:
");
$sList->display();
?>
输出:
Originals list:
1 2 3 2 2 4 1
List after removing duplicates:
1 2 3 4