📅  最后修改于: 2020-10-15 04:49:55             🧑  作者: Mango
在此程序中,给定的三叉树将转换为相应的双向链表。
三叉树是一个分层的数据结构,其中每个节点最多可以有三个孩子。这可以通过以预排序方式遍历三叉树来完成,即根->左子->中间子->右子。首先,遍历根节点并将其添加到列表中。然后,分别添加其左,中和右子树。
三元树:
对应的双向链表:
#Represent a node of ternary tree
class Node:
def __init__(self,data):
self.data = data;
self.left = None;
self.middle = None;
self.right = None;
class TernaryTreeToDLL:
def __init__(self):
#Represent the root of ternary tree
self.root = None;
#Represent the head and tail of the doubly linked list
self.head = None;
self.tail = None;
#convertTernaryToDLL() will convert the given ternary tree to corresponding doubly linked list
def convertTernaryToDLL(self, node):
#Checks whether node is None
if(node == None):
return;
#Keep three pointers to all three children
left = node.left;
middle = node.middle;
right = node.right;
#If list is empty then, add node as head of the list
if(self.head == None):
#Both head and tail will point to node
self.head = self.tail = node;
node.middle = None;
#head's left will point to None
self.head.left = None;
#tail's right will point to None, as it is the last node of the list
self.tail.right = None;
#Otherwise, add node to the end of the list
else:
#node will be added after tail such that tail's right will point to node
self.tail.right = node;
#node's left will point to tail
node.left = self.tail;
node.middle = None;
#node will become new tail
self.tail = node;
#As it is last node, tail's right will point to None
self.tail.right = None;
#Add left child of current node to the list
self.convertTernaryToDLL(left);
#Then, add middle child of current node to the list
self.convertTernaryToDLL(middle);
#Then, add right child of current node to the list
self.convertTernaryToDLL(right);
#displayDLL() will print out the nodes of the list
def displayDLL(self):
#Node current will point to head
current = self.head;
if(self.head == None):
print("List is empty");
return;
print("Nodes of generated doubly linked list: ");
while(current != None):
#Prints each node by incrementing pointer.
print(current.data),
current = current.right;
tree = TernaryTreeToDLL();
#Add nodes to the ternary tree
tree.root = Node(5);
tree.root.left = Node(10);
tree.root.middle = Node(12);
tree.root.right = Node(15);
tree.root.left.left = Node(20);
tree.root.left.middle = Node(40);
tree.root.left.right = Node(50);
tree.root.middle.left = Node(24);
tree.root.middle.middle = Node(36);
tree.root.middle.right = Node(48);
tree.root.right.left = Node(30);
tree.root.right.middle = Node(45);
tree.root.right.right = Node(60);
#Converts the given ternary tree to doubly linked list
tree.convertTernaryToDLL(tree.root);
#Displays the nodes present in the list
tree.displayDLL();
输出:
Nodes of the generated doubly linked list:
5 10 20 40 50 12 24 36 48 15 30 45 60
#include
//Represent a node of the ternary tree
struct node{
int data;
struct node *left;
struct node *middle;
struct node *right;
};
//Represent the root of the ternary tree
struct node *root;
//Represent the head and tail of the doubly linked list
struct node *head, *tail = NULL;
//createNode() will create a new node
struct node* createNode(int data){
//Create a new node
struct node *newNode = (struct node*)malloc(sizeof(struct node));
//Assign data to newNode
newNode->data = data;
return newNode;
}
//convertTernaryToDLL() will convert the given ternary tree to corresponding doubly linked list
void convertTernaryToDLL(struct node *node) {
//Checks whether node is NULL
if(node == NULL)
return;
//Keep three pointers to all three children
struct node *left = node->left;
struct node *middle = node->middle;
struct node *right = node->right;
//If list is empty then, add node as head of the list
if(head == NULL) {
//Both head and tail will point to node
head = tail = node;
node->middle = NULL;
//head's left will point to NULL
head->left = NULL;
//tail's right will point to NULL, as it is the last node of the list
tail->right = NULL;
}
//Otherwise, add node to the end of the list
else {
//node will be added after tail such that tail's right will point to node
tail->right = node;
//node's left will point to tail
node->left = tail;
node->middle = NULL;
//node will become new tail
tail = node;
//As it is last node, tail's right will point to NULL
tail->right = NULL;
}
//Add left child of current node to the list
convertTernaryToDLL(left);
//Then, add middle child of current node to the list
convertTernaryToDLL(middle);
//Then, add right child of current node to the list
convertTernaryToDLL(right);
}
//displayDLL() will print out the nodes of the list
void displayDLL() {
//Node current will point to head
struct node *current = head;
if(head == NULL) {
printf("List is empty\n");
return;
}
printf("Nodes of generated doubly linked list: \n");
while(current != NULL) {
//Prints each node by incrementing pointer.
printf("%d ",current->data);
current = current->right;
}
printf("\n");
}
int main()
{
//Add nodes to the ternary tree
root = createNode(5);
root->left = createNode(10);
root->middle = createNode(12);
root->right = createNode(15);
root->left->left = createNode(20);
root->left->middle = createNode(40);
root->left->right = createNode(50);
root->middle->left = createNode(24);
root->middle->middle = createNode(36);
root->middle->right = createNode(48);
root->right->left = createNode(30);
root->right->middle = createNode(45);
root->right->right = createNode(60);
//Converts the given ternary tree to doubly linked list
convertTernaryToDLL(root);
//Displays the nodes present in the list
displayDLL();
return 0;
}
输出:
Nodes of generated doubly linked list:
5 10 20 40 50 12 24 36 48 15 30 45 60
public class TernaryTreeToDLL {
//Represent a node of ternary tree
public static class Node{
int data;
Node left;
Node middle;
Node right;
public Node(int data) {
this.data = data;
}
}
//Represent the root of the ternary tree
public Node root;
//Represent the head and tail of the doubly linked list
Node head, tail = null;
//convertTernaryToDLL() will convert the given ternary tree to corresponding doubly linked list
public void convertTernaryToDLL(Node node) {
//Checks whether node is null
if(node == null)
return;
//Keep three pointers to all three children
Node left = node.left;
Node middle = node.middle;
Node right = node.right;
//If list is empty then, add node as head of the list
if(head == null) {
//Both head and tail will point to node
head = tail = node;
node.middle = null;
//head's left will point to null
head.left = null;
//tail's right will point to null, as it is the last node of the list
tail.right = null;
}
//Otherwise, add node to the end of the list
else {
//node will be added after tail such that tail's right will point to node
tail.right = node;
//node's left will point to tail
node.left = tail;
node.middle = null;
//node will become new tail
tail = node;
//As it is last node, tail's right will point to null
tail.right = null;
}
//Add left child of current node to the list
convertTernaryToDLL(left);
//Then, add middle child of current node to the list
convertTernaryToDLL(middle);
//Then, add right child of current node to the list
convertTernaryToDLL(right);
}
//displayDLL() will print out the nodes of the list
public void displayDLL() {
//Node current will point to head
Node current = head;
if(head == null) {
System.out.println("List is empty");
return;
}
System.out.println("Nodes of generated doubly linked list: ");
while(current != null) {
//Prints each node by incrementing the pointer.
System.out.print(current.data + " ");
current = current.right;
}
System.out.println();
}
public static void main(String[] args) {
TernaryTreeToDLL tree = new TernaryTreeToDLL();
//Add nodes to the ternary tree
tree.root = new Node(5);
tree.root.left = new Node(10);
tree.root.middle = new Node(12);
tree.root.right = new Node(15);
tree.root.left.left = new Node(20);
tree.root.left.middle = new Node(40);
tree.root.left.right = new Node(50);
tree.root.middle.left = new Node(24);
tree.root.middle.middle = new Node(36);
tree.root.middle.right = new Node(48);
tree.root.right.left = new Node(30);
tree.root.right.middle = new Node(45);
tree.root.right.right = new Node(60);
//Converts the given ternary tree to doubly linked list
tree.convertTernaryToDLL(tree.root);
//Displays the nodes present in the list
tree.displayDLL();
}
}
输出:
Nodes of generated doubly linked list:
5 10 20 40 50 12 24 36 48 15 30 45 60
using System;
namespace DoublyLinkedList
{
public class Program
{
//Represent a node of ternary tree
public class Node{
public T data;
public Node left;
public Node middle;
public Node right;
public Node(T value) {
data = value;
}
}
public class TernaryTreeToDLL{
//Represent the root of the ternary tree
public Node root;
//Represent the head and tail of the doubly linked list
public Node head = null;
public Node tail = null;
//convertTernaryToDLL() will convert the given ternary tree to corresponding doubly linked list
public void convertTernaryToDLL(Node node) {
//Checks whether node is null
if(node == null)
return;
//Keep three pointers to all three children
Node left = node.left;
Node middle = node.middle;
Node right = node.right;
//If list is empty then, add node as head of the list
if(head == null) {
//Both head and tail will point to node
head = tail = node;
node.middle = null;
//head's left will point to null
head.left = null;
//tail's right will point to null, as it is the last node of the list
tail.right = null;
}
//Otherwise, add node to the end of the list
else {
//node will be added after tail such that tail's right will point to node
tail.right = node;
//node's left will point to tail
node.left = tail;
node.middle = null;
//node will become new tail
tail = node;
//As it is last node, tail's right will point to null
tail.right = null;
}
//Add left child of current node to the list
convertTernaryToDLL(left);
//Then, add middle child of current node to the list
convertTernaryToDLL(middle);
//Then, add right child of current node to the list
convertTernaryToDLL(right);
}
//displayDLL() will print out the nodes of the list
public void displayDLL() {
//Node current will point to head
Node current = head;
if(head == null) {
Console.WriteLine("List is empty");
return;
}
Console.WriteLine("Nodes of generated doubly linked list: ");
while(current != null) {
//Prints each node by incrementing the pointer.
Console.Write(current.data + " ");
current = current.right;
}
Console.WriteLine();
}
}
public static void Main()
{
TernaryTreeToDLL tree = new TernaryTreeToDLL();
//Add nodes to the ternary tree
tree.root = new Node(5);
tree.root.left = new Node(10);
tree.root.middle = new Node(12);
tree.root.right = new Node(15);
tree.root.left.left = new Node(20);
tree.root.left.middle = new Node(40);
tree.root.left.right = new Node(50);
tree.root.middle.left = new Node(24);
tree.root.middle.middle = new Node(36);
tree.root.middle.right = new Node(48);
tree.root.right.left = new Node(30);
tree.root.right.middle = new Node(45);
tree.root.right.right = new Node(60);
//Converts the given ternary tree to doubly linked list
tree.convertTernaryToDLL(tree.root);
//Displays the nodes present in the list
tree.displayDLL();
}
}
}
输出:
Nodes of generated doubly linked list:
5 10 20 40 50 12 24 36 48 15 30 45 60
data = $data;
}
}
class TernaryTreeToDLL{
//Represent the root of ternary tree
public $root;
//Represent the head and tail of the doubly linked list
public $head;
public $tail;
function __construct(){
$this->head = NULL;
$this->tail = NULL;
$this->root = NULL;
}
//convertTernaryToDLL() will convert the given ternary tree to corresponding doubly linked list
function convertTernaryToDLL($node) {
//Checks whether node is NULL
if($node == NULL)
return;
//Keep three pointers to all three children
$left = $node->left;
$middle = $node->middle;
$right = $node->right;
//If list is empty then, add node as head of the list
if($this->head == NULL) {
//Both head and tail will point to node
$this->head = $this->tail = $node;
$node->middle = NULL;
//head's left will point to NULL
$this->head->left = NULL;
//tail's right will point to NULL, as it is the last node of the list
$this->tail->right = NULL;
}
//Otherwise, add node to the end of the list
else {
//node will be added after tail such that tail's right will point to node
$this->tail->right = $node;
//node's left will point to tail
$node->left = $this->tail;
$node->middle = NULL;
//node will become new tail
$this->tail = $node;
//As it is last node, tail's right will point to NULL
$this->tail->right = NULL;
}
//Add left child of current node to the list
$this->convertTernaryToDLL($left);
//Then, add middle child of current node to the list
$this->convertTernaryToDLL($middle);
//Then, add right child of current node to the list
$this->convertTernaryToDLL($right);
}
//displayDLL() will print out the nodes of the list
function displayDLL() {
//Node current will point to head
$current = $this->head;
if($this->head == NULL) {
print("List is empty
");
return;
}
print("Nodes of generated doubly linked list:
");
while($current != NULL) {
//Prints each node by incrementing pointer.
print($current->data . " ");
$current = $current->right;
}
print("
");
}
}
$tree = new TernaryTreeToDLL();
//Add nodes to the ternary tree
$tree->root= new Node(5);
$tree->root->left = new Node(10);
$tree->root->middle = new Node(12);
$tree->root->right = new Node(15);
$tree->root->left->left = new Node(20);
$tree->root->left->middle = new Node(40);
$tree->root->left->right = new Node(50);
$tree->root->middle->left = new Node(24);
$tree->root->middle->middle = new Node(36);
$tree->root->middle->right = new Node(48);
$tree->root->right->left = new Node(30);
$tree->root->right->middle = new Node(45);
$tree->root->right->right = new Node(60);
//Converts the given ternary tree to doubly linked list
$tree->convertTernaryToDLL($tree->root);
//Displays the nodes present in the list
$tree->displayDLL();
?>
输出:
Nodes of generated doubly linked list:
5 10 20 40 50 12 24 36 48 15 30 45 60