给定数组N的大小,任务是构造一个大小为 N 的数组,其中包含正整数元素,使得该数组所有元素的立方和是一个完美的平方。
注意:允许重复整数。
例子:
Input: N = 1
Output: 4
Explanation: Cube of 4 is 64, and 64 is perfect square.
Input: N = 6
Output: 5 10 5 10 5 5
Explanation: Cubic sum of array element is (5)3 + (10)3 + (5)3 + (10)3 + (5)3 + (5)3 = 2500, and 2500 is perfect square.
方法:想法是构造大小为N 的数组,其中包含前N 个自然数。如果仔细观察,
cubic sum of first N natural number: (1)3 + (2)3 + (3)3 + (4)3 + …….(N)3 is always perfect square.
as
下面是上述方法的实现。
C++
// C++ program to construct an array
// that cube sum of all element
// is a perfect square
#include
using namespace std;
// Function to create
// and print the array
void constructArray(int N)
{
int arr[N];
// initialise the array of size N
for (int i = 1; i <= N; i++) {
arr[i - 1] = i;
}
// Print the array
for (int i = 0; i < N; i++) {
cout << arr[i] << ", ";
}
}
// Driver code
int main()
{
int N = 6;
constructArray(N);
return 0;
}
Java
// Java program to construct array
// that cube sum of all element
// is a perfect square
import java.util.*;
class GFG{
// Function to create
// and print the array
static void constructArray(int N)
{
int arr[] = new int[N];
// Initialise the array of size N
for(int i = 1; i <= N; i++)
{
arr[i - 1] = i;
}
// Print the array
for(int i = 0; i < N; i++)
{
System.out.print(arr[i] + ", ");
}
}
// Driver code
public static void main(String[] args)
{
int N = 6;
constructArray(N);
}
}
// This code is contributed by AbhiThakur
Python3
# Python3 program to construct
# array that cube sum of all
# element is a perfect square
# Function to create
# and print the array
def constructArray(N):
arr = [0] * N
# Initialise the array of size N
for i in range(1, N + 1):
arr[i - 1] = i;
# Print the array
for i in range(N):
print(arr[i], end = ", ")
# Driver code
N = 6;
constructArray(N);
# This code is contributed by grand_master
C#
// C# program to construct array
// that cube sum of all element
// is a perfect square
using System;
class GFG{
// Function to create
// and print the array
static void constructArray(int N)
{
int []arr = new int[N];
// Initialise the array of size N
for(int i = 1; i <= N; i++)
{
arr[i - 1] = i;
}
// Print the array
for(int i = 0; i < N; i++)
{
Console.Write(arr[i] + ", ");
}
}
// Driver code
public static void Main()
{
int N = 6;
constructArray(N);
}
}
// This code is contributed by Code_Mech
Javascript
输出:
1, 2, 3, 4, 5, 6,
时间复杂度: O(N) ,其中 N 是数组的大小。
空间复杂度: O(1)
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