先决条件：运算符重载
给定两个 NxN 维度的矩阵mat1[][]和mat2[][] ，任务是使用运算符重载执行矩阵运算。
例子：
Input: arr1[][] = { {1, 2, 3}, {4, 5, 6}, {1, 2, 3}}, arr2[][] = { {1, 2, 3}, {4, 5, 16}, {1, 2, 3}}
Output:
Addition of two given Matrices is:
2 4 6
8 10 22
2 4 6
Substraction of two given Matrices is:
0 0 0
0 0 -10
0 0 0
Multiplication of two given Matrices is:
12 18 44
30 45 110
12 18 44
Input: arr1[][] = { {11, 2, 3}, {4, 5, 0}, {1, 12, 3}}, arr2[][] = { {1, 2, 3}, {41, 5, 16}, {1, 22, 3}}
Output:
Addition of two given Matrices is :
12 4 6
45 10 16
2 34 6
Substraction of two given Matrices is :
10 0 0
-37 0 -16
0 -10 0
Multiplication of two given Matrices is :
96 98 74
209 33 92
496 128 204
方法：
要重载+ 、 – 、 *运算符，我们将创建一个名为 matrix 的类，然后创建一个公共函数来重载运算符。
- 要重载运算符“+”，请使用原型：
Return_Type classname :: operator +(Argument list) { // Function Body }例如：
Let there are two matrix M1[][] and M2[][] of same dimensions. Using Operator Overloading M1[][] and M2[][] can be added as M1 + M2.
In the above statement M1 is treated hai global and M2[][] is passed as an argument to the function “void Matrix::operator+(Matrix x)“.
In the above overloaded function, the appproach for addition of two matrix is implemented by treating M1[][] as first and M2[][] as second Matrix i.e., Matrix x(as the arguments).
- 要重载运算符“-”，请使用原型：
Return_Type classname :: operator -(Argument list) { // Function Body }例如：
Let there are two matrix M1[][] and M2[][] of same dimensions. Using Operator Overloading M1[][] and M2[][] can be added as M1 – M2.
In the above statement M1 is treated hai global and M2[][] is passed as an argument to the function “void Matrix::operator-(Matrix x)“.
In the above overloaded function, the appproach for substraction of two matrix is implemented by treating M1[][] as first and M2[][] as second Matrix i.e., Matrix x(as the arguments).
- 要重载运算符“*”，请使用原型：
Return_Type classname :: operator *(Argument list) { // Function Body }Let there are two matrix M1[][] and M2[][] of same dimensions. Using Operator Overloading M1[][] and M2[][] can be added as M1 * M2.
In the above statement M1 is treated hai global and M2[][] is passed as an argument to the function “void Matrix::operator*(Matrix x)“.
In the above overloaded function, the appproach for multiplication of two matrix is implemented by treating M1[][] as first and M2[][] as second Matrix i.e., Matrix x(as the arguments).
下面是上述方法的实现：
C++
// C++ program for the above approach
#include "bits/stdc++.h"
#define rows 50
#define cols 50
using namespace std;
int N;
// Class for Matrix operator overloading
class Matrix {
// For input Matrix
int arr[rows][cols];
public:
// Function to take input to arr[][]
void input(vector >& A);
void display();
// Functions for operator overloading
void operator+(Matrix x);
void operator-(Matrix x);
void operator*(Matrix x);
};
// Functions to get input to Matrix
// array arr[][]
void Matrix::input(vector >& A)
{
// Travarse the vector A[][]
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
arr[i][j] = A[i][j];
}
}
}
// Function to display the element
// of Matrix
void Matrix::display()
{
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Print the element
cout << arr[i][j] << ' ';
}
cout << endl;
}
}
// Function for addition of two Matrix
// using operator overloading
void Matrix::operator+(Matrix x)
{
// To store the sum of Matrices
int mat[N][N];
// Travarse the Matrix x
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Add the corresponding
// blocks of Matrices
mat[i][j] = arr[i][j]
+ x.arr[i][j];
}
}
// Display the sum of Matrices
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Print the element
cout << mat[i][j] << ' ';
}
cout << endl;
}
}
// Function for subtraction of two Matrix
// using operator overloading
void Matrix::operator-(Matrix x)
{
// To store the difference of Matrices
int mat[N][N];
// Travarse the Matrix x
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Subtract the corresponding
// blocks of Matrices
mat[i][j] = arr[i][j]
- x.arr[i][j];
}
}
// Display the difference of Matrices
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Print the element
cout << mat[i][j] << ' ';
}
cout << endl;
}
}
// Function for multiplication of
// two Matrix using operator
// overloading
void Matrix::operator*(Matrix x)
{
// To store the multiplication
// of Matrices
int mat[N][N];
// Travarse the Matrix x
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Initialise current block
// with value zero
mat[i][j] = 0;
for (int k = 0; k < N; k++) {
mat[i][j] += arr[i][k]
* (x.arr[k][j]);
}
}
}
// Display the multiplication
// of Matrices
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
// Print the element
cout << mat[i][j] << ' ';
}
cout << endl;
}
}
// Driver Code
int main()
{
// Dimension of Matrix
N = 3;
vector > arr1
= { { 1, 2, 3 },
{ 4, 5, 6 },
{ 1, 2, 3 } };
vector > arr2
= { { 1, 2, 3 },
{ 4, 5, 16 },
{ 1, 2, 3 } };
// Declare Matrices
Matrix mat1, mat2;
// Take Input to matrix mat1
mat1.input(arr1);
// Take Input to matrix mat2
mat2.input(arr2);
// For addition of matrix
cout << "Addition of two given"
<< " Matrices is : \n";
mat1 + mat2;
// For substraction of matrix
cout << "Substraction of two given"
<< " Matrices is : \n";
mat1 - mat2;
// For multiplication of matrix
cout << "Multiplication of two"
<< " given Matrices is : \n";
mat1* mat2;
return 0;
} Addition of two given Matrices is :
2 4 6
8 10 22
2 4 6
Substraction of two given Matrices is :
0 0 0
0 0 -10
0 0 0
Multiplication of two given Matrices is :
12 18 44
30 45 110
12 18 44
如果您想与行业专家一起参加直播课程，请参阅Geeks Classes Live