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📜  使用给定矩形块可以形成的最大正方形

📅  最后修改于: 2021-10-23 09:09:22             🧑  作者: Mango

给定一个正整数数组arr[] ,其中数组的每个元素代表矩形块的长度。任务是找到可以使用矩形块形成的正方形的最大长度。

例子:

方法:

  1. 按降序对给定数组进行排序。
  2. 将最大边长(比如maxLength )初始化为 0。
  3. 遍历数组arr[]并且如果arr[i] > maxLength然后增加 maxLength 并检查此条件以进行下一次迭代。
  4. 如果上述条件不满足,则中断循环并打印maxLength

下面是上述方法的实现:

C++
// C++ program for the above approach
#include 
using namespace std;
 
// Function to find maximum side
// length of square
void maxSide(int a[], int n)
{
    int sideLength = 0;
 
    // Sort array in asc order
    sort(a, a + n);
 
    // Traverse array in desc order
    for (int i = n - 1; i >= 0; i--) {
 
        if (a[i] > sideLength) {
            sideLength++;
        }
        else {
            break;
        }
    }
    cout << sideLength << endl;
}
 
// Driver Code
int main()
{
    int N = 6;
 
    // Given array arr[]
    int arr[] = { 3, 2, 1, 5, 2, 4 };
 
    // Function Call
    maxSide(arr, N);
    return 0;
}


Java
// Java program for the above approach
import java.util.Arrays;
 
class GFG{
     
// Function to find maximum side
// length of square
static void maxSide(int a[], int n)
{
    int sideLength = 0;
 
    // Sort array in asc order
    Arrays.sort(a);
 
    // Traverse array in desc order
    for(int i = n - 1; i >= 0; i--)
    {
       if (a[i] > sideLength)
       {
           sideLength++;
       }
       else
       {
           break;
       }
    }
    System.out.println(sideLength);
}
     
// Driver code
public static void main (String[] args)
{
    int N = 6;
 
    // Given array arr[]
    int arr[] = new int[]{ 3, 2, 1,
                           5, 2, 4 };
     
    // Function Call
    maxSide(arr, N);
}
}
 
// This code is contributed by Pratima Pandey


Python3
# Python3 program for the above approach
 
# Function to find maximum side
# length of square
def maxSide(a, n):
 
    sideLength = 0
 
    # Sort array in asc order
    a.sort
 
    # Traverse array in desc order
    for i in range(n - 1, -1, -1):
        if (a[i] > sideLength):
            sideLength += 1
        else:
            break
             
    print(sideLength)
     
# Driver code
N = 6
 
# Given array arr[]
arr = [ 3, 2, 1, 5, 2, 4 ]
 
# Function Call
maxSide(arr, N)
 
# This code is contributed by divyeshrabadiya07


C#
// C# program for the above approach
using System;
class GFG{
     
// Function to find maximum side
// length of square
static void maxSide(int []a, int n)
{
    int sideLength = 0;
 
    // Sort array in asc order
    Array.Sort(a);
 
    // Traverse array in desc order
    for(int i = n - 1; i >= 0; i--)
    {
        if (a[i] > sideLength)
        {
            sideLength++;
        }
        else
        {
            break;
        }
    }
    Console.Write(sideLength);
}
     
// Driver code
public static void Main()
{
    int N = 6;
 
    // Given array arr[]
    int []arr = new int[]{ 3, 2, 1,
                           5, 2, 4 };
     
    // Function Call
    maxSide(arr, N);
}
}
 
// This code is contributed by Code_Mech


Javascript


输出:
3

时间复杂度: O(N*log N)
辅助空间: O(1)

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