Java中的 Duration withSeconds(long) 方法和示例

Java.time 包中Duration 类的withSeconds(long)方法用于获取此持续时间的不可变副本，其中指定的秒数作为参数传递。

句法：

public Duration withSeconds(long amountOfSeconds)

参数：此方法接受参数amountOfSeconds ，它是秒数。

返回值：此方法返回作为参数传递的秒的持续时间。

下面的示例说明了 Duration.withSeconds() 方法：

示例 1：

// Java code to illustrate withSeconds() method
  
import java.time.Duration;
  
public class GFG {
    public static void main(String[] args)
    {
  
        // Get the amount of seconds
        long amountOfSeconds = 300;
  
        // Duration using parse() method
        Duration duration
            = Duration.parse("P2DT3H4M");
  
        // Get the duration in seconds
        // using withSeconds() method
        System.out.println(duration
                               .withSeconds(amountOfSeconds));
    }
}

输出：

PT5M

示例 2：

// Java code to illustrate withSeconds() method
  
import java.time.Duration;
  
public class GFG {
    public static void main(String[] args)
    {
  
        // Get the amount of seconds
        long amountOfSeconds = 3000;
  
        // Duration using ofHours() method
        Duration duration
            = Duration.ofHours(5);
  
        // Get the duration in seconds
        // using withSeconds() method
        System.out.println(duration
                               .withSeconds(amountOfSeconds));
    }
}

输出：

PT50M

参考： https://docs.oracle.com/javase/9/docs/api/ Java/time/Duration.html#withSeconds-long-