Java中的 Duration ofSeconds(long, long) 方法及示例
Java.time 包中Duration 类的ofSeconds(long, long)方法用于获取 1 秒格式的持续时间。在此方法中,秒数以 1 秒格式的总秒数计算,即每秒 1 秒。第二个参数 nanoAdjustment 用于调整以 nanoSeconds 为单位的秒数。
句法:
public static Duration ofSeconds(long seconds, long nanoAdjustment)
参数:此方法接受两个参数:
- seconds :这是秒数。它可以是积极的或消极的。
- nanoAdjustment :这是要在几秒钟内进行的调整。
返回值:此方法返回一个以 1 秒格式表示时间的Duration 。
异常:如果输入的秒数超过 Duration 的容量,此方法将抛出ArithmeticException 。
下面的示例说明了 Duration.ofSeconds() 方法:
示例 1:
// Java code to illustrate ofSeconds() method
import java.time.Duration;
public class GFG {
public static void main(String[] args)
{
// input number of Seconds
long noOfSeconds = 214545;
// input nanoSeconds adjustment to be made
long nanoSecAdjust = 10000;
// Duration using ofSeconds() method
Duration duration
= Duration.ofSeconds(noOfSeconds);
Duration duration1
= Duration.ofSeconds(noOfSeconds,
nanoSecAdjust);
System.out.println("Duration without adjustment: "
+ duration.getSeconds());
System.out.println("Duration with adjustment: "
+ duration1.getSeconds());
}
}
输出:
Duration without adjustment: 214545
Duration with adjustment: 214545
示例 2:
// Java code to illustrate ofSeconds() method
import java.time.Duration;
public class GFG {
public static void main(String[] args)
{
// input number of Seconds
long noOfSeconds = 214545;
// input nanoSeconds adjustment to be made
long nanoSecAdjust = -10000;
// Duration using ofSeconds() method
Duration duration
= Duration.ofSeconds(noOfSeconds);
Duration duration1
= Duration.ofSeconds(noOfSeconds,
nanoSecAdjust);
System.out.println("Duration without adjustment: "
+ duration.getSeconds());
System.out.println("Duration with adjustment: "
+ duration1.getSeconds());
}
}
输出:
Duration without adjustment: 214545
Duration with adjustment: 214544
参考: https://docs.oracle.com/javase/9/docs/api/ Java/time/Duration.html#ofSeconds-long-long-