📅  最后修改于: 2022-03-11 14:48:53.686000             🧑  作者: Mango
private bool noBricksLeft () {
for (int i = 0; i < brick.GetLength(0); i++) {
// inverted your condition; we can short-circuit
// and just return false
if (brickLocation[i, 2] != 0)
return false;
}
// every brick passed our condition, so return true
return true;
}